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Mamont248 [21]
3 years ago
14

When a certain number is trebled then decreased by 1, the result is twice as much as 5 more than the number? What is the number?

Mathematics
1 answer:
ddd [48]3 years ago
7 0
3x-1=2(x+5)
3x-1=2x+10
x-1=10
x=11

Hope this helps :)
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Answers for both boxes please ​
sleet_krkn [62]

Answer:

x = -5  y = -3

Step-by-step explanation:

-3x + 2y = 9

multiply the 2nd equation by 3 to set it up for elimination

3(x - 3y)= 3(4)

3x-9y = 12

so now combine both to add

-3x + 2y = 9

3x - 9y = 12

Adding both gives you

-7y = 21

divide both by -7 and you get

y = -3

and you substitute y back into equation to get x

x - 3 (-3) = 4   gives you

x + 9 = 4

x = 4 - 9

x = -5

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If f(x)=-3+7 and g(x)=-7+3, what is the value of f(-3) - g(3)
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