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bagirrra123 [75]
2 years ago
8

Kaya is riding her dirt bike eastward on a dirt road. She spots a pothole ahead. Kaya slows her car from 18.0 m/s to 6.5 m/s in

6.5 s. What is her acceleration?
Mathematics
1 answer:
DochEvi [55]2 years ago
3 0
First of all why is she riding a dirt bike we have cars in 2021
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is there picture?

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Every 3 hours, a machine produces 60 baskets what is the unit rate
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20 per hour

Step-by-step explanation:

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Can someone please explain #7 to me
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$28

Step-by-step explanation:

You subtract $44 from $100 since that is the cast of the jeans. Then get left remaining with $56. Since he wants to buy 2 shirts only you divide 56 by 2 to then equaling $28. So then each shirt is $28.

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Can someone plz help me solved this problem! Need help ASAP! Help me !
lana66690 [7]

Answer:  5, 8

<u>Step-by-step explanation:</u>

The difference between 3 times a number and -8 is BETWEEN 23 and 32

Note: "difference" means subtraction --> 3x - (-8)  --> 3x + 8

               23 < 3x + 8 < 32

               15 < 3x        < 24          <em> subtracted 8 from all 3 sides</em>

-->             5 <   x        <   8          <em>divided 3 from all 3 sides</em>

 

5 0
3 years ago
x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

x=-cos(t)+2sin(t)

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

Where solutions r_1,r_2...,r_n are the roots from which the general solution can be found.

For real roots the solution is given by:

y(t)=c_1e^{r_1t} +c_2e^{r_2t}

For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

Where:

r_1_,_2=\lambda \pm \mu i

Let's find the solution for x''+x=0 using the previous information:

The characteristic equation is:

r^{2} +1=0

So, the roots are given by:

r_1_,_2=0\pm \sqrt{-1} =\pm i

Therefore, the solution is:

x(t)=c_1cos(t)+c_2sin(t)

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of x(t) in order to find the constants c_1 and c_2:

x'(t)=-c_1sin(t)+c_2cos(t)

Evaluating the initial conditions:

x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1

And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

x=-cos(t)+2sin(t)

3 0
3 years ago
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