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jeyben [28]
3 years ago
8

H=39t-5t2 find all the values of t for which the rockets hight is 22 meters

Mathematics
1 answer:
uysha [10]3 years ago
5 0
I believe that for this question you will use the quadratic equation which is: (-b +/- sqrt(b^2-4(a)(c))/2a   Plug in -5=a, 39=b, 22=c and that should give you 2 answers for t.  
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(22, 23)

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A flagpole casts a shadow 8.5 meters long. if an algebra student 1.6 meters tall casts a shadow 2.0 meters long at the same time
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Sidana [21]

Answer:

(1, -16)

Step-by-step explanation:

<u>Vertex form</u> of a quadratic equation:

y=a(x-h)^2+k

where:

  • (h, k) is the vertex
  • a is some constant

Given equation:

x^2-2x-15=y

To convert the given quadratic equation to vertex form, <u>complete the square</u>.

Add 15 to both sides:

\implies x^2-2x-15+15=y+15

\implies x^2-2x=y+15

Add the square of half the coefficient of the x term to both sides:

\implies x^2-2x+\left(\dfrac{-2}{2}\right)^2=y+15+\left(\dfrac{-2}{2}\right)^2

\implies x^2-2x+1=y+16

Factor the left side:

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Subtract 16 from both sides:

\implies (x-1)^2-16=y

\implies y=(x-1)^2-16

Comparing with the vertex form:

\implies h=1, \quad k=-16

Therefore, the vertex of the given quadratic is (1, -16)

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