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jeyben [28]
3 years ago
8

H=39t-5t2 find all the values of t for which the rockets hight is 22 meters

Mathematics
1 answer:
uysha [10]3 years ago
5 0
I believe that for this question you will use the quadratic equation which is: (-b +/- sqrt(b^2-4(a)(c))/2a   Plug in -5=a, 39=b, 22=c and that should give you 2 answers for t.  
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Yuri [45]
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\sqrt(-2 + 3) ^{2} + (-2 - 5) ^{2}

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6 0
3 years ago
How would you calculate the area and perimeter of 3yd 6yd 5yd 10yds
spayn [35]
Okay, start with the smaller square, you know the side length is 3 and that the width is 5, multiply this together:
3 * 5 = 15

That's the smaller left side of this shape, now the bigger side, divide the 10 yards at the bottom by 2 to properly represent the other side then multiply this by the 6 over there.
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| | Ghostgate | |
3 0
3 years ago
How many balls can Michael predict to hit if he is pitched 20 balls?
Vinvika [58]
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7 0
3 years ago
167÷2=83.5 how to solve
gavmur [86]

Step-by-step explanation:

162/2 (the same as 162÷2) =83.5

83.5+83.5=162

^

that was two times to add so we know for sure that 162/2=83.5. Theres no special way to solve it since its just dived by <em>two</em>. Its just 162÷2=83.5

Hope this helps.

3 0
2 years ago
Read 2 more answers
Use pascal's triangle to expand the following binomial expression <br>1.(2k-1/3)⁶​
Gwar [14]

9514 1404 393

Answer:

  64k^6 -64k^5 +(80/3)k^4 -(160/27)k^3 +(20/27)k^2 -(4/81)k +1/729

Step-by-step explanation:

The row of Pascal's triangle we need for a 6th power expansion is ...

  1, 6, 15, 20, 15, 6, 1

These are the coefficients of the products (a^(n-k))(b^k) in the expansion of (a+b)^n as k ranges from 0 to n.

Your expansion is ...

  1(2k)^6(-1/3)^0 +6(2k)^5(-1/3)^1 +15(2k)^4(-1/3)^2 +20(2k)^3(-1/3)^3 +...

     15(2k)^2(-1/3)^4 +6(2k)^1(-1/3)^5 +1(2k)^0(-1/3)^6

  = 64k^6 -64k^5 +(80/3)k^4 -(160/27)k^3 +(20/27)k^2 -(4/81)k +1/729

7 0
2 years ago
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