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kykrilka [37]
3 years ago
9

Simplify -4(x+6)+2(x-2)

Mathematics
2 answers:
Ber [7]3 years ago
8 0

Answer:

-2x -26

Step-by-step

kati45 [8]3 years ago
6 0

Answer:

-2x-28

Step-by-step explanation:

We can apply the distributive property then combine like terms for a simpler equation.

-4(x+6)+2(x-2)\\\\-4x-24+2x-4\\\\-2x-28

Hope this helped!

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1/2x-2/3>3 enter your answer using interval notation
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So basically u keep the x on one side and the rest on the other. Get a common denominator. to get rid of the half u times both sides by 2.
hope this helps

7 0
3 years ago
How do historians define the term "causation​
Naily [24]

Your answer would be the relationship between two events in which one leads directly to the other occurring

5 0
3 years ago
Write an equation of the line below.
Dafna11 [192]

Answer:

\large\boxed{y=4x+3}

Step-by-step explanation:

The slope-intercept form of an equation of aline:

y=mx+b

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept</em>

The formula of a slope:

m=\dfraxc{y_2-y_1}{x_2-x_1}

From the graph we have the points:

(-2, -5)

y-intercept (0, 3) → <em>b = 3</em>

Calculate the slope:

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Put the value of the slope and the y-intercept to the equation of a line:

y=4x+3

3 0
4 years ago
It’s a new semester! Students are grouped into three clubs, which each has 10, 4 and 5 students. In how many ways can teacher se
ozzi

Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.

So there are 3 clubs:

  • Club A, with 10 students.
  • Club B, with 4 students.
  • Club C, with 5 students.

The possible combinations of 2 students from different clubs are

  • Club A with club B
  • Club A with club C
  • Club B with club C.

The number of combinations for each of these is given by the product between the number of students in the club, so we get:

  • Club A with club B: 10*4 = 40
  • Club A with club C: 10*5 = 50
  • Club B with club C. 4*5 = 20

For a total of 40 + 50 + 20 = 110 different combinations.

This means that there are 110 different ways in which 2 students from different clubs can be selected.

If you want to learn more about combination and selections, you can read:

brainly.com/question/251701

6 0
2 years ago
Ive been having this question for a while "what do you use first PEMDAS or Order of Operations". Well you might say it doesn't m
IgorLugansk [536]

Answer:

Order of Operations was aught at a younger age for those just grasping the idea of multiplication and division. Exposing PEMDAS at a young age would confuse them too much, hence the order of operation groups, addition/subtraction and multiplication/division. So for the second example problem, PEMDAS would be correct because it does involve you to use parentheses as well as exponents to solve for. Very easy to mix up between order of operations and PEMDAS, but just look at it as if Order of operations is a beginner level of PEMDAS.

Step-by-step explanation:

5 0
3 years ago
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