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Rainbow [258]
3 years ago
6

Who is correct and why?

Mathematics
1 answer:
Masja [62]3 years ago
3 0

i believe the answer is the last one

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In the right triangle ABC with right angle at A , the inradius is 2cm. If the hypothenuse BC=10cm , determine the perimeter and
trasher [3.6K]

Answer: 24cm

Step-by-step explanation:

Inradius = r

c = the hypothenuse

a & b = the other 2 sides of the triangle

Inradius formula: r = 1/2 * (a+b-c)

Plug in what we know.

2 = 1/2 * (a+b-10)

Multiply both sides by 2.

2*2 = 1/2 * (a+b-10) * 2

4 = a+b-10

Add 10 to both sides.

4+10 = a+b-10+10

14 = a+b

Perimeter formula: P=a+b+c

Plug in what we know

(remember a+b=14).

P=14 + 10

P = 24

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The reflection of H(-10,-11) is H'(10, -11). What is the reflection
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James deposited $575 into a bank account that earned 5.5% simple interest each year.
Leona [35]
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575+ 71.875 = 646.875
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4 years ago
Katy's driveway is 120 ft. How many yd is Katy's driveway?
umka2103 [35]
40 yards are in 120 feet
8 0
4 years ago
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Identify the sets that contain 2 as an element. (Check all that apply.)Check All That Apply{2, 3, 4, 5, ...}{2, 3, 4, 5, ...}{0,
Lady bird [3.3K]

Question:

Identify the sets that contain 2 as an element. (Check all that apply.)

A.\ \{2, 3, 4, 5, ...\}

B.\ \{0, 1, 4, 9, ...\}

C.\ \{2, \{2\} \}

D.\ \{\{2\}, \{\{2\}\}\}

E.\ \{\{2\}, \{2, \{2\}\}\}

F.\ \{\{\{2\}\}\}

Answer:

A.\ \{2, 3, 4, 5, ...\}

C.\ \{2, \{2\} \}

Step-by-step explanation:

Required

For which of the options is 2 an element

A.\ \{2, 3, 4, 5, ...\}

The elements of this set starts from 2, then 3 and continues as thus.

Hence: 2 is an element

B.\ \{0, 1, 4, 9, ...\}

From the given elements in the above set, 2 is not listed.

Hence: 2 is not an element of this set

C.\ \{2, \{2\} \}

Here, 2 is listed as an element, 2 is also listed as a subset.

Since 2 is listed as an element, then 2 is an element of the set.

D.\ \{\{2\}, \{\{2\}\}\}

Here, 2 is listed as a subset of {2} and also as a subset of subset of {{2}}.

Since 2 is not listed as an element itself, then 2 is not an element of the set.

E.\ \{\{2\}, \{2, \{2\}\}\}

Here, 2 is listed as a subset of {2} and also as a subset of subset of {2,{2}}. This set only contains subsets, i.e. 2 is not listed as a direct element of the set.

Hence: 2 is not an element of the set

F.\ \{\{\{2\}\}\}

Here, 2 is listed as a subset of subset of {{2}}. This set only contains subsets, i.e. 2 is not listed as a direct element of the set.

Hence: 2 is not an element of the set

5 0
3 years ago
Read 2 more answers
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