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2 answers:
Answer a < (a + b)/2 < b
Solve the first inequality.
a < (a + b)/2
2a < a + b
a < b
Solve the second inequality.
(a + b)/2 < b
a + b < 2b
a < b
Both inequalities are true. Therefore, a < (a + b)/2 < b.
Step-by-step explanation:
Step-by-step explanation:
a < (a + b)/2 < b
Solve the first inequality.
a < (a + b)/2
2a < a + b
a < b
Solve the second inequality.
(a + b)/2 < b
a + b < 2b
a < b
Both inequalities are true. Therefore, a < (a + b)/2 < b.
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