Problem 1
The largest value would be 1 and the smallest would be
-1.
To get a product of 1, either all are 1 or two of the
variables are -1 and the other one is 1.
Largest value = (1)^2 * (1)^3 * (1)^4 =1
Smallest value = (- 1)^2 * (- 1)^3 * (1)^4 = -1
The difference is:
largest value – smallest value = 1 – (-1) = 2
<span>Therefore the answer is letter D.</span>
Problem 2
% loss = (final price – initial price) * 100%/ initial
price
where, final price per dozen = ( $2.50 / piece) (12 piece
/ dozen) = $30
Therefore,
% loss = ($30 - $33) * 100 / $33
% loss = - 300/ 33 = 9 1/11
<span>Therefore the answer is <span>letter C.</span></span>
It is not reasonable because if someone were to add 4 toppings, the price would be $20.41. However, if a person were to add 3 toppings using that equation, the price would $19.02.
2x+4-3x=0
-4 -4
2x-3x=-4
-1x=-4
_ _
-1 -1
x=4
so the answer is x=4
Answer:
72z+176
Step-by-step explanation:
36z+28+8z+40+12z+60+48+16z=
36z+8z+12z+16z+28+40+60+48=
72z+176
