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ale4655 [162]
3 years ago
9

Consider the following planes. 3x − 2y + z = 1, 2x + y − 3z = 3

Mathematics
1 answer:
prisoha [69]3 years ago
3 0

Solve for any of the variables; for instance, z:

z=1-3x+2y

z=-\dfrac{3-2x-y}3

Then

1-3x+2y=-\dfrac{3-2x-y}3\implies11x-5y=6\implies\begin{cases}y=\frac{11x-6}5\\z=1-3x+\frac{22x-12}5\end{cases}

Let x=t; then the intersection is given by the vector-valued function

\vec r(t)=\left(t,\dfrac{11t-6}5,1-3t+\dfrac{22t-12}5\right)

or

\vec r(t)=\left(t,\dfrac{11t-6}5,\dfrac{7t-7}5\right)

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Answer:

// C++ Program to arithmetic operationf on 2 Numbers using Recursion

// Comments are used for explanatory purpose

#include <bits/stdc++.h>

using namespace std;

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int add10(int m, int n)

{

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// Main Methods Starts here

int main()

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int m, n; // 2 Variables m and n declared as integer

cin>>m; // accept input for m

cin>>n; // accept input for n

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return 0;

}

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Answer:

True

Step-by-step explanation:

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