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azamat
2 years ago
5

Pls help? :( brainliest if correct

Mathematics
2 answers:
brilliants [131]2 years ago
6 0

Answer:

Option C is the Correct Answer

wolverine [178]2 years ago
4 0
Cone and triangular prism
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Simplify.<br><br><br><br> Enter your answer, in simplest radical form, in the box.
puteri [66]
24.75 rounded might be 25
5 0
3 years ago
Read 2 more answers
How many solutions does this system have?
Julli [10]

Answer:

one solution

Step-by-step explanation:

* Lets start to solve the question

- The 1st equation x - y = -4

- The 2nd equation 3x + y = 8

- We will use the elimination method to solve this system of equation

∵ x - y = -4 ⇒ (1)

∵ 3x + y = 8 ⇒ (2)

- Add the two equation (1) and (2) to eliminate y

∴ x + 3x = -4 + 8

∴ 4x = 4

- Divide both sides by 4

∴ x = 1

- Substitute the value of x in equation (1) or equation (2) to find

  the value of y

- We will use equation (1)

∴ 1 - y = -4

Subtract 1 from both sides

∴ -y = -5

- Divide both sides by -1

∴ y = 5

∴ The solution is (1 , 5)

* The system has one solution

6 0
3 years ago
Read 2 more answers
0x-7*9 = 0<br>Solve for x.<br>​
Helga [31]

Answer:

Undefined

<em>Step </em><em>by</em><em> step</em><em> </em><em>explaination:</em>

<em> </em>

by order of operations we know that we multiply first;

so, 0x-(7*9)=0

1) Multiply the ones in brackets first:

0x-63=0

2) To make X the subject perform the opposite operation:

0x-64+63=0+63

0x=63

3) Divide 0 on both sides;

0x/0= 63/0

therefore; <u>x is undefined</u>

3 0
2 years ago
Read 2 more answers
Find a polynomial with integer coefficients that satisfies the given conditions. R has degree 4 and zeros 3 − 3i and 2, with 2 a
dolphi86 [110]

Answer:

The required polynomial is P(x)=x^4-10x^3+46x^2-96x+72.

Step-by-step explanation:

If a polynomial has degree n and c_1,c_2,...,c_n are zeroes of the polynomial, then the polynomial is defined as

P(x)=a(x-c_1)(x-c_2)...(x-x_n)

It is given that the polynomial R has degree 4 and zeros 3 − 3i and 2. The multiplicity of zero 2 is 2.

According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.

Since 3-3i is zero, therefore 3+3i is also a zero.

Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is

R(x)=(x-3+3i)(x-3-3i)(x-2)(x-2)

R(x)=((x-3)+3i)((x-3)-3i)(x-2)^2

R(x)=(x-3)^2-(3i)^2((x-3)-3i)(x-2)^2     [a^2-b^2=(a-b)(a+b)]

R(x)=(x^2-6x+9-9(i)^2((x-3)-3i)(x-2)^2

R(x)=(x^2-6x+18)(x^2-4x+4)                [i^2=-1]

R(x)=(x^2-6x+18)(x^2-4x+4)

R(x)=x^4-10x^3+46x^2-96x+72

Therefore the required polynomial is P(x)=x^4-10x^3+46x^2-96x+72.

3 0
3 years ago
What integer $x$ satisfies $\frac{1}{4}&lt;\frac{x}{7}&lt;\frac{1}{3}$?
Zarrin [17]

If 1/4 < x/7 < 1/3, then

7/4 < x < 7/3

1.75 < x < 2.333…

so that x = 2.

6 0
2 years ago
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