Answer:
one solution
Step-by-step explanation:
* Lets start to solve the question
- The 1st equation x - y = -4
- The 2nd equation 3x + y = 8
- We will use the elimination method to solve this system of equation
∵ x - y = -4 ⇒ (1)
∵ 3x + y = 8 ⇒ (2)
- Add the two equation (1) and (2) to eliminate y
∴ x + 3x = -4 + 8
∴ 4x = 4
- Divide both sides by 4
∴ x = 1
- Substitute the value of x in equation (1) or equation (2) to find
the value of y
- We will use equation (1)
∴ 1 - y = -4
Subtract 1 from both sides
∴ -y = -5
- Divide both sides by -1
∴ y = 5
∴ The solution is (1 , 5)
* The system has one solution
Answer:
Undefined
<em>Step </em><em>by</em><em> step</em><em> </em><em>explaination:</em>
<em> </em>
by order of operations we know that we multiply first;
so, 0x-(7*9)=0
1) Multiply the ones in brackets first:
0x-63=0
2) To make X the subject perform the opposite operation:
0x-64+63=0+63
0x=63
3) Divide 0 on both sides;
0x/0= 63/0
therefore; <u>x is undefined</u>
Answer:
The required polynomial is 
.
Step-by-step explanation:
If a polynomial has degree n and 
are zeroes of the polynomial, then the polynomial is defined as
It is given that the polynomial R has degree 4 and zeros 3 − 3i and 2. The multiplicity of zero 2 is 2.
According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.
Since 3-3i is zero, therefore 3+3i is also a zero.
Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is
![[a^2-b^2=(a-b)(a+b)]](https://tex.z-dn.net/?f=%5Ba%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5D)
![[i^2=-1]](https://tex.z-dn.net/?f=%5Bi%5E2%3D-1%5D)
Therefore the required polynomial is .
