For f(x)=1/x^2-3
Find
A) f(3)
B) f(2-h)
If f(x)=1/x^2-3, then f(3) = 1 / 3^2 - 3. The exponentiation here must be carried out first: f(3) = 1/9 - 3. Then f(3) = 1/9 - 27/9 = -26/9
If f(x)=1/x^2-3, then f(2-h) = 1 / [2-h]^2 - 3. This result may be left as is or expanded. In expanded form, we have:
1
f(2-h) = ------------------ - 3
4-4h +h^2
Answer:
3x² – 2x – 8
=> 3x² – 6x + 4x – 8
=> 3x( x – 2 ) + 4( x – 2 )
=> ( 3x + 4 ) ( x – 2 )
Therefore,
Either, 3x + 4 = 0
3x = - 4
x = - 4/3 (Ans)
And,
x – 2 = 0
x = 2 (Ans)
Answer:
I believe it is y equals 3 minus 2x.
