How many pounds of each kind of candy (hard at $2 per pound, and soft at $4 per pound) must be mixed to

12% is 90% of what number?

Andrews [41]

12% = 0.12

90% = 0.9

$0.12 = 0.9 \times x\\\\x = \frac{0.12}{0.9}=\boxed{1.33333}$

7 0

3 years ago

PLEASE HELP MEEEEE !!!!!! Like rn

Dovator [93]

Answer:

Your screen is black hun

Step-by-step explanation:

4 0

3 years ago

Would you need to use the chain rule to find the derivative of this function?

Nutka1998 [239]

Answer:

TRUE. We need to use the chain rule to find the derivative of the given function.

Step-by-step explanation:

Chain rule to find the derivative,

We have to find the derivative of F(x)

If F(x) = f[g(x)]

Then F'(x) = f'[g(x)].g'(x)

Given function is,

y = $\sqrt{2x+3}$

Here g(x) = (2x + 3)

and f[g(x)] = $\sqrt{2x+3}$

$\frac{dy}{dx}=\frac{d}{dx}(\sqrt{2x+3}).\frac{d}{dx} (2x+3)$

y' = $\frac{1}{2}(2x+3)^{(1-\frac{1}{2})}.(2)$

= $(2x+3)^{-\frac{1}{2}}$

y' = $\frac{1}{\sqrt{2x+3}}$

Therefore, it's true that we need to use the chain rule to find the derivative of the given function.

8 0

4 years ago

Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and

Brums [2.3K]

Answer:

$t=\frac{51.6-48}{\frac{1.1}{\sqrt{10}}}=10.349$

$p_v =P(t_9>10.349)=1.34x10^{-6}$

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the the actual mean is significantly higher than 48 MPa at 5% of significance.

Step-by-step explanation:

1) Data given and notation

$\bar X=51.6$ represent the sample mean

$s=1.1$ represent the standard deviation for the sample

$n=10$ sample size

$\mu_o =48$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the mean score is higher than 48, the system of hypothesis would be:

Null hypothesis: $\mu \geq 48$

Alternative hypothesis: $\mu > 48$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{51.6-48}{\frac{1.1}{\sqrt{10}}}=10.349$

Calculate the P-value

First we find the degrees of freedom:

$df=n-1=10-1=9$

Since is a one-side upper test the p value would be:

$p_v =P(t_9>10.349)=1.34x10^{-6}$

Conclusion

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the the actual mean is significantly higher than 48 MPa at 5% of significance.

5 0

3 years ago

What is the length of segment AB?<br> Consider the diagram.<br> 7,9,18,25

Mrrafil [7]

Answer:

9

Step-by-step explanation:

It is congruent to the other side.

5 0

3 years ago