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3 years ago

Rewrite the equation below so that it does not have fractions. 2+2/3x = 3/4

Mathematics

1 answer:

aleksandr82 [10.1K]3 years ago

8 0

Answer:

Step-by-step explanation:

2/3x + 2 = 3/4

12(2/3x + 2 = 3/4)

8x + 24 = 9

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What is the midpoint of a line segment with the ends 8,-3 and -5,-9

grandymaker [24]

Midpoint = (8-5),(-3-9) / 2
= (3,-12)/2
= (3/2,-6)

7 0

4 years ago

2 ⋅ √ 2 + √ 8 - simplify

Ivanshal [37]

Answer:

$4\sqrt2$

Step-by-step explanation:

$2\sqrt{2} +\sqrt{8}=2\sqrt{2}+2\sqrt{2}=4\sqrt{2}$

6 0

2 years ago

Read 2 more answers

How do I do this question folks?

horsena [70]

Answer:

Correct answer: B

Step-by-step explanation:

Syntax: in piecewise functions such as the one attached, the "if:" section shows the domain, or x-axis values which that function pertains to.

In the graph, you can see that the graph is defined for $-3\leq x < 1$ (not-including 1 because there is an open hole there, indicating it is not part of the domain), and $2\leq x\leq 4$ .

Now that we know the domain, we can attach it to the graphs that lie on those domains.

We see that the leftmost line appears to have a positive slope and a negative y-intercept, and that the second line should have a positive y-intercept and a negative slope.

At this point, you can just start crossing off answers that don't meet this criteria.

Cheers!!

7 0

3 years ago

What is the probability that e) A fair coin lands Heads 6 times in a row? f) A fair coin lands Heads 4 times out of 5 flips? g)

cricket20 [7]

Answer:

e) 1.56%

f) 15.62%

h) 0.879%

g) 11.72%

Step-by-step explanation:

What we will do is solve point by point.

e) A fair coin lands Heads 6 times in a row?

We have the following:

Total number of possible outcomes = 2 ^ 6 = 64

Number of favorable outcomes = 1

Required probability = 1/64 = 1.56%

f) A fair coin lands Heads 4 times out of 5 flips

We have the following:

Total number of possible outcomes = 2 ^ 5 = 32

Number of favorable outcomes = 5C4

nCr = n! / (r! * (n-r)!)

5C4 = 5! / (4! * (5-4)!) = 5

Required probability = 5/32 = 15.62%

g) he bit string has exactly two 1s, given that the string begins with a 1 if you pick a bit string from the set of all bit strings of length ten?

We have the following:

Total number of possible outcomes = 2 ^ 10 = 1024

Number of ways in which a position excluding the start of the string can be chosen is 9C1

Total number of favorable outcomes = 9C1

9C1 = 9! / (1! * (9-1)!) = 9

Required probability = 9/1024 = 0.879%

h)The bit string has the sum of its digits equal to seven if you pick a bit string from the set of all bit strings of length ten?

We have the following:

Total number of possible outcomes = 2 ^ 10 = 1024

For the sum of the digits to be 7 there has to be 7 ones.

Number of ways in which 7 position can be chosen is 10C7.

Total number of favorable outcomes = 10C7

10C7 = 10! / (7! * (10-7)!) = 120

Required probability = 120/1024 = 11.72%

5 0

4 years ago

I need help on how absolute mean devian works can some one help me

Maru [420]

Answer:

Not sure if you meant deviation but hope this helps ya

Step-by-step explanation:

Absolute deviation (MAD) of a data set is the average distance between each data value and the mean. Mean absolute deviation is a way to describe variation in a data set. Mean absolute deviation helps us get a sense of how "spread out" the values in a data set are.

8 0

3 years ago