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3 years ago

If the GFC of two number is 1, they are called relatively prime. Find three sets of relatively prime numbers

Mathematics

1 answer:

Ilia_Sergeevich [38]3 years ago

8 0

I think, 2, 5 and 7?

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Find the new amount given the original amount and the percent of change. $35,000; 7% decrease

SpyIntel [72]

Answer:

7%=50

34950 7% decrease

35050 7% increase

Step-by-step explanation:

if 35000 is before the 7% decrease then it would be 34950

if after 35050

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3 years ago

Define the powers and how it is different to use a negative and positive power

lesya [120]

Answer:

Hi here is answer hope it helps

Step-by-step explanation:

A positive exponent tells us how many times to multiply a base number, and a negative exponent tells us how many times to divide a base number.

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3 years ago

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Anastasy [175]

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Find the length of the following curve. If you have a grapher, you may want to graph the curve to see what it looks like.

stepladder [879]

The length of the curve $y = \frac{1}{27}(9x^2 + 6)^\frac 32$ from x = 3 to x = 6 is 192 units

<h3>How to determine the length of the curve?</h3>

The curve is given as:

$y = \frac{1}{27}(9x^2 + 6)^\frac 32$ from x = 3 to x = 6

Start by differentiating the curve function

$y' = \frac 32 * \frac{1}{27}(9x^2 + 6)^\frac 12 * 18x$

Evaluate

$y' = x(9x^2 + 6)^\frac 12$

The length of the curve is calculated using:

$L =\int\limits^a_b {\sqrt{1 + y'^2}} \, dx$

This gives

$L =\int\limits^6_3 {\sqrt{1 + [x(9x^2 + 6)^\frac 12]^2}\ dx$

Expand

$L =\int\limits^6_3 {\sqrt{1 + x^2(9x^2 + 6)}\ dx$

This gives

$L =\int\limits^6_3 {\sqrt{9x^4 + 6x^2 + 1}\ dx$

Express as a perfect square

$L =\int\limits^6_3 {\sqrt{(3x^2 + 1)^2}\ dx$

Evaluate the exponent

$L =\int\limits^6_3 {3x^2 + 1} \ dx$

Differentiate

$L = x^3 + x|\limits^6_3$

Expand

L = (6³ + 6) - (3³ + 3)

Evaluate

L = 192

Hence, the length of the curve is 192 units