Answer:
The entire population is measured in both cases, so the actual difference in means can be computed and a confidence interval should not be used.
Step-by-step explanation:
A student working on a report about mathematicians decides to find the 98% confidence interval for the difference in mean age at the time of math discovery for Greek mathematicians versus Egyptian mathematicians. The student finds the ages at the time of math discovery for members of both groups, which include all Greek and Egyptian mathematicians, and uses a calculator to determine the 98% confidence interval based on the t distribution, <u>the entire population is measured in both cases, so the actual difference in means can be computed and a confidence interval should not be used.</u> There is no as such explanation of this scenario, its just the answer mentioned above.
Answer:
20
Step-by-step explanation:
Just plug 3 into the equation for x:
6/3 + 2(3)^2
2 + 18
2 + 18 = 20
-13+9=-4
When you add a positive number to a negative number the answer will get closer to 0 and then progress up in positive numbers. In this case we are finding which of the numbers equals -4 when added to -13. Remember, if you add a negative to a negative you will get a negative.
-13+-17=-30 This is the wrong answer.
-13+-9=-21 This is the wrong answer.
-13+17=4 This is the wrong answer. (This is positive 4 we are trying to find -4)
-13+9=-4 This is the right answer
Therefore X=9
Answer:
The answer is x=2i√5,−2i√5
Answer:
Step-by-step explanation:
<h2 /><h2>
<u>Consider</u></h2>
<h2>
<u>W</u><u>e</u><u> </u><u>K</u><u>n</u><u>o</u><u>w</u><u>,</u></h2>
So, on substituting all these values, we get
<h2>Hence,</h2>
▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬
<h2>ADDITIONAL INFORMATION :-</h2>
Sign of Trigonometric ratios in Quadrants
- sin (90°-θ) = cos θ
- cos (90°-θ) = sin θ
- tan (90°-θ) = cot θ
- csc (90°-θ) = sec θ
- sec (90°-θ) = csc θ
- cot (90°-θ) = tan θ
- sin (90°+θ) = cos θ
- cos (90°+θ) = -sin θ
- tan (90°+θ) = -cot θ
- csc (90°+θ) = sec θ
- sec (90°+θ) = -csc θ
- cot (90°+θ) = -tan θ
- sin (180°-θ) = sin θ
- cos (180°-θ) = -cos θ
- tan (180°-θ) = -tan θ
- csc (180°-θ) = csc θ
- sec (180°-θ) = -sec θ
- cot (180°-θ) = -cot θ
- sin (180°+θ) = -sin θ
- cos (180°+θ) = -cos θ
- tan (180°+θ) = tan θ
- csc (180°+θ) = -csc θ
- sec (180°+θ) = -sec θ
- cot (180°+θ) = cot θ
- sin (270°-θ) = -cos θ
- cos (270°-θ) = -sin θ
- tan (270°-θ) = cot θ
- csc (270°-θ) = -sec θ
- sec (270°-θ) = -csc θ
- cot (270°-θ) = tan θ
- sin (270°+θ) = -cos θ
- cos (270°+θ) = sin θ
- tan (270°+θ) = -cot θ
- csc (270°+θ) = -sec θ
- sec (270°+θ) = cos θ
- cot (270°+θ) = -tan θ
