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3 years ago

Solve for x . help anyone ?

Mathematics

2 answers:

Stella [2.4K]3 years ago

5 0

5 I think. I’m pretty sure it is though

guajiro [1.7K]3 years ago

3 0

Step-by-step explanation:

$\cos(60) = \frac{x}{10} \\ x = 5$

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75 is the product of Greg’s height and 5

KatRina [158]

Answer:

Let Greg's height be = x

According to the question;

$= > x \times 5 = 75 \\ \\ = > x = \frac{75}{5} \\ \\ = > x = 15$

So, Greg's height (x) = 15 years

7 0

3 years ago

Read 2 more answers

The relationship between numbers in list X and list Y follows the rule Y = X +2.05 what diagram shows this relationship

dexar [7]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

y=x+2.05

This is a linear equation ( equation of a line)

To graph the line find the intercepts

The y-intercept is the value of y when the value of x is equal to zero

For x=0

y=0+2.05=2.5

The y-intercept is the point (0,2.05)

The x-intercept is the value of x when the value of y is equal to zero

For y=0

0=x+2.05

x=-2.05

The x-intercept is the point (-2.05,0)

To graph the line plot the intercepts and then join the points

using graphing tool

see the attached figure

6 0

3 years ago

What is the range of this exponential function y=9^×+2

matrenka [14]

Answer4/8 x 69

Step-by-step explanation:

You add Tekashi

5 0

3 years ago

Fourteen pounds of beans are distributed equally into 10 bags to give out at the food bank. How many pounds of beans are in each

mario62 [17]

Answer:

The answer is 1.4 lbs of beans in each bag

Step-by-step explanation:

You divide 14 by 10 and you will get 1.4

6 0

3 years ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

ANSWER:

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

SOLUTION:

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

3 years ago