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3 years ago

5

Please help if you want brianleist!! :) uhm don't mind update- NO LINkS child.. Ty!

2 answers:

Sav [38]3 years ago

6 0

Answer:

12

Step-by-step explanation:

Just count the dots

GrogVix [38]3 years ago

3 0

12 since there are 12 x’s:)

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Need help with #8 & #14 PLEASE!!

juin [17]

Answer:

8 (see work)

14. 2x^2 -4x^2 +3

Step-by-step explanation:

There's attached work for explanation

8 0

3 years ago

Solve the following equation: lim x->0 sin3x/5x^3-4x.

goblinko [34]

Usual limit of sin is sinX/X--->1, when X--->0

sin3x/5x^3-4x=0/0?, sin3x/3x--->1 when x --->0, so sin3x/5x^3-4x= [3x. sin3x / 3x] /(5x^3-4x)=(sin3x / 3x) . (3x/5x^3-4x)
=(sin3x / 3x) . (3/5x^2- 4)
finally lim sin3x/5x^3-4x=lim (sin3x / 3x) .(3/5x^2- 4)=1x(3/-4)= - 3/4
x----->0 x---->0

3 0

3 years ago

Together, Kyle and Tyler traveled 425 miles to the beach. If Kyle traveled 240 miles, how far did Tyler travel? A) 2x = 425 B) x

Snezhnost [94]

Answer:

the answer is x=185

Step-by-step explanation:

x+240=425

-240 -240

x= 185

3 0

4 years ago

Read 2 more answers

For the following integral, give a power or simple exponential function that if integrated on a similar infinite domain will hav

zhannawk [14.2K]

Answer:

hello your question is incomplete attached below is the complete question

answer :

for I1 = $\frac{1}{x^2} + \frac{4}{x^3}$ The integral converges

for I2 = $\frac{2x + 6}{2(x^2 + 6x + 4 )}$ The integral diverges

for I3 = $\frac{1}{x^2}$ The integral converges

for I4 = 1 The integral diverges

Step-by-step explanation:

The similar integrands and the prediction ( conclusion )

for I1 = $\frac{1}{x^2} + \frac{4}{x^3}$ The integral converges

for I2 = $\frac{2x + 6}{2(x^2 + 6x + 4 )}$ The integral diverges

for I3 = $\frac{1}{x^2}$ The integral converges

for I4 = 1 The integral diverges

attached below is a detailed solution

5 0

3 years ago

What are the coordinates of P' if P (-5,-4) undergoes a dilation, centered at the origin, with a scale factor of K=2?

Margaret [11]

Answer:

$P' = (-10,-8)$

Step-by-step explanation:

Given

$P = (-5,-4)$

$k =2$

Required

Determine the image P'

P' is calculated by multiplying P and k.

i.e.

$P' = P * k$

This gives:

$P' = (-5,-4) * 2$

$P' = (-5* 2,-4* 2)$

$P' = (-10,-8)$

<em>Hence, the image P' after dilating P is (-10,-8)</em>

7 0

3 years ago