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brilliants [131]
3 years ago
5

514 A restaurant's menu features appetizers, 7 entrées, and 3 dessertsA customer orders only oneappetizer, only one entrée, and

onlyone dessert.How many different meals can be ordered? A.3 B.15 C.35 D.105

Mathematics
1 answer:
yuradex [85]3 years ago
8 0
Simple...there'a a LOT of combinations...

so to simply solve this;there is 5 appetizers, 7 entrees and 3 desserts....

Just take 5*7=35

and 

35*3=105

Thu,s there is 105 combinations possible to make.

Thus, your answer, D.
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Assignment: \bold{Simplify \ Equation: \ 7\left(3\sqrt{2}x\right)-3\left(3\sqrt{16}x\right)-3\left(3\sqrt{8}x\right)}

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Answer: \boxed{\bold{3\sqrt{2}x-36x}}

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\bold{7\cdot \:3\sqrt{2}x-3\cdot \:3\sqrt{16}x-3\cdot \:3\sqrt{8}x}

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[ Step Three ] Rewrite Equation

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