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jarptica [38.1K]
2 years ago
12

73 divi by 844 helppppppppppppp

Mathematics
1 answer:
Mice21 [21]2 years ago
6 0

Answer:

0.1

Step-by-step explanation:

73/844=0.08649=0.1(After rounding)

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Use the standard norml distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justif
dalvyx [7]

Answer:

E) we will use t- distribution because is un-known,n<30

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Step-by-step explanation:

<u>Step:-1</u>

Given sample size is n = 23<30 mortgage institutions

The mean interest rate 'x' = 0.0365

The standard deviation 'S' = 0.0046

the degree of freedom = n-1 = 23-1=22

99% of confidence intervals t_{0.01} =2.82  (from tabulated value).

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x±t_{0.01} \frac{S}{\sqrt{n-1} }

0.0365±2.82 \frac{0.0046}{\sqrt{23-1} }

0.0365±2.82 \frac{0.0046}{\sqrt{22} }

0.0365±2.82 \frac{0.0046}{4.690 }

using calculator

0.0365±0.00276

Confidence interval is

(0.0365-0.00276,0.0365+0.00276)

(0.0338,0.0392)

the mean value is lies between in this confidence interval

(0.0338,0.0392).

<u>Answer:-</u>

<u>using t- distribution because is unknown,n<30,and the interest rates are not normally distributed.</u>

4 0
3 years ago
What is 9+m=1.5<br><br><br>i need the answer for m
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Answer:

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Step-by-step explanation:

Given

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divide by nine
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Answer:

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Since they are all different activities and don't relate you can put different bars to put the different activities and use the left to indicate the amount of students and grow the bar according to the amount of students in that activity; each bar stands for a different activity, the y-intercept is for the amount of students, the bar will grow 'up' according to the amount of students.

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