Question

evaluate g(p) times h(p) by modeling or by using the distributive property. g(p)=(p-2) and h(p)=(p^3+4p^2-2)

Answer 1

we are given

$g(p)=(p-2)$

$h(p)=(p^3+4p^2-2)$

now, we can multiply them

$g(p)\times h(p)=(p-2)\times (p^3+4p^2-2)$

$g(p)\times h(p)=p\times p^3+p\times 4p^2-p\times 2-2\times p^3-2\times 4p^2-2\times -2$

now, we can simplify it

$g(p)\times h(p)=p^4+4p^3-2p-2p^3-8p^2+4$

so, we get

$g(p)\times h(p)=p^4+2p^3-8p^2-2p+4$.............Answer