800 is 10 times as much as
1 answer:
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The equation of a circle with center at (h,k) and radius r is
we are given
center is at (3,2)
solving for y
take the derivitive to find the slope at any point
we can use point slope form
for apoint (h,k) and slope m, the equation is
y-k=m(x-h)
not sure if you want in terms of what
I'll just say for a point (h,k)
so we get
where
that's the equation of the tangent line at (h,k) for arbitrary values of r
do the plots and other stuff yourself
we are given
center is at (3,2)
solving for y
take the derivitive to find the slope at any point
we can use point slope form
for apoint (h,k) and slope m, the equation is
y-k=m(x-h)
not sure if you want in terms of what
I'll just say for a point (h,k)
so we get
where
that's the equation of the tangent line at (h,k) for arbitrary values of r
do the plots and other stuff yourself