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zhuklara [117]
2 years ago
15

Three students were lined up in a row. Lucas was to the left of Fatima, but not necessarily next to her. The student wearing the

blue shirt was to the right of the student wearing the white shirt. The student wearing the black shirt was to the left of Benjamin. Benjamin was to the left of Fatima. What was the order of the students from left to right?
Mathematics
1 answer:
kirill [66]2 years ago
5 0

Answer:

Benjamin then student wearing black t-shirt then the student wearing white then who wear blue then lucas then fatima

Step-by-step explanation:

where fatima is the first one then the others beside her one by one

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Given f(x)=8x+1 and g(x)=f(x-2) which equation represents g
castortr0y [4]

Given f(x) = 8x + 1 and g(x) = f(x − 2), which equation represents g substitute x-2 for x in f(x). we have. g(x)=8(x-2)+1. =8x-16+1. =8x-15.

Answer:

Step-by-step explanation:

4 0
3 years ago
Expand using the properties and rules for logarithms
malfutka [58]

Consider expression \log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).

1. Use property

\log_a\dfrac{b}{c}=\log_ab-\log_ac.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.

2. Use property

\log_abc=\log_ab+\log_ac.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.

3. Use property

\log_ab^k=k\log_ab.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.

4. Use property

\log_{a^k}b=\dfrac{1}{k}\log_ab.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.

Answer: correct option is B.

7 0
3 years ago
Please answer <br><br> 8 + 9 x 1 x 2/2
12345 [234]
The answer would be 17.
7 0
3 years ago
Read 2 more answers
If you can explain your answer that’d be great!! Thank you!
Rasek [7]

Answer:

A(t)=A_{0}e^{\frac{ln(\frac{1}{2})}{22}t}

Step-by-step explanation:

This half life exponential decay equation goes by the formula:

A(t)=A_{0}e^{kt}

Where

k=\frac{ln(\frac{1}{2})}{Half-Life}

Since half life is given as 22, we plug that into "Half-Life" in the formula for k and then plug in the formula for k into the exponential decay formula:

So,

k=\frac{ln(\frac{1}{2})}{Half-Life}\\k=\frac{ln(\frac{1}{2})}{22}

Now

A(t)=A_{0}e^{\frac{ln(\frac{1}{2})}{22}t}

third choice is correct.

8 0
3 years ago
Please show work I have more pictures otw
Hatshy [7]

Answer:

ou

Step-by-step explanation:

op

3 0
3 years ago
Read 2 more answers
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