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Murrr4er [49]
3 years ago
11

What are the solutions of x^2 - 5x+7 = 0 ?​

Mathematics
1 answer:
lesya692 [45]3 years ago
4 0

Answer:

C.

Step-by-step explanation:

We use the Quadractic Formula: x = \frac{-b +/-\sqrt{b^2-4ac} }{2a}

*Excuse the bad ± (plus or minus) sign. It wouldn't let me put it in the equation maker

<em>a</em> = 1

<em>b</em> = -5

<em>c</em> = 7

Step 1: Plug in our variables

\frac{5+/-\sqrt{5^2-4(1)(7)} }{2(1)}

Step 2: Solve

\frac{5+/-\sqrt{25-28} }{2}

\frac{5+/-\sqrt{-3} }{2}

√-3 is equal to √-1 times √3, and √-1 is equal to imaginary i

Thus, we have:

(5 ± i√3)/2 or (5 + i√3)/2 and (5 - i√3)/2

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The median of Rae's data is 2.22 minutes, and the median of Doris' data is 2.14 minutes. The interquartile range for Rae is , an
JulsSmile [24]

Complete question :

Rae and Doris are training to swim a 200-meter freestyle race. The table lists their practice times during training camp.

Rae’s Times(minutes)-2.12, 2.01, 2.46, 2, 2.22, 2.31, 2.23

doris times(minutes)-2.32, 2.19, 2.26, 2.03, 2.11, 2.14, 2.07

The median of Raes data is(drop down box answers, 2,2.03,2.14,2.22)minutes,and the median of doris data is(drop down box answers, 2,2.03,2.14,2.22)minutes. The interquartile range for rae is(drop down box answers, 0.01,0.13,0.26,0.30), and the interquartile range for doris is(drop down box answers, 0.02,0.06,0.18,0.19). The two data sets overlap(drop down box answers,very little, a lot

Answer:

Rae's median = 2.22

Rae's IQR = 0.30

DORIS median = 2.14

Doris IQR = 0.19

Step-by-step explanation:

Given :

Rae's time :

Ordered data : 2, 2.01, 2.12, 2.22, 2.23, 2.31, 2.46

Median = 1/2(n+1)th term ; n = 7

Median = 1/2(8) = 4th term

Median = 2.22

Q1 = 1/4(8)th term

Q1 = 2nd term = 2.01

Q3 = 3/4(n + 1)th term

Q3 = 3/4(8)th term

Q3 = 6th term = 2.31

Interquartile range = Q3 - Q1 = 2.31 - 2.01 = 0.30

DORIS Data:

Ordered data: 2.03, 2.07, 2.11, 2.14, 2.19, 2.26, 2.32

Median = 1/2(n+1)th term ; n = 7

Median = 1/2(8) = 4th term

Median = 2.14

Q1 = 1/4(8)th term

Q1 = 2nd term = 2.07

Q3 = 3/4(n + 1)th term

Q3 = 3/4(8)th term

Q3 = 6th term = 2.26

Interquartile range = Q3 - Q1 = 2.26 - 2.07 = 0.19

6 0
3 years ago
Plzzzzz answer this question about density mass and volume!!!!!!!!!
nataly862011 [7]

Answer:

13.896 kg

Step-by-step explanation:

You can find the mass of the bar by first finding the volume.

V = BH

where B = area of the base (the trapezium), and

H = height (distance trapezium between bases)

The area of a trapezium is

A = (b1 + b2)h/2

where b1 and b2 are the lengths of the bases of the trapezium (the parallel sides), and

h = the altitude of the trapezium (distance between the bases of the trapezium)

V = (b1 + b2)h/2 * H

V = (12 cm + 6 cm)(5 cm)/2 * 16 cm

V = 720 cm^3

The volume of the bar is 720 cm^3.

Now we use the density and the volume to find the mass.

density = mass/volume

mass = density * volume

mass = 19.3 g/cm^3 * 720 cm^3

mass = 13,896 g

Now we convert grams into kilograms.

1 kg = 1000 g

mass = 13,896 g * (1 kg)/(1000 g)

mass = 13.896 kg

Answer: 1.3896 kg

6 0
4 years ago
4,567.89
In-s [12.5K]

Answer:

I got 40210.1

Step-by-step explanation:

4,567.89+7,894.56=12462.45

12462.45+1,232.45=13694.9

13694.9+1,474.10=15169

15169+2,585.20=17754.2

17754.2+3696.36=21450.56

21450.56+3,214.56=24665.12

24665.12+6,545.65=31210.77

31210.77+7,898.78=39109.55

39109.55+1.100.55=40210.1

5 0
3 years ago
If C(m) = 0.50m + 30 represents the cost of renting a car, how many miles were driven if cost is $130
FinnZ [79.3K]

Answer:

m=#miles

so 130= .5m+30

subtract 30 from each side

100$= .5m than divide .5 to isolate m

m= 200

Step-by-step explanation:

3 0
3 years ago
Johnny had $8.25 in quarters. He went to the laundromat and spent all of his quarters doing laundry. Which equation describes ho
ss7ja [257]

8.25 / 25 = n

The "/" is division.

7 0
3 years ago
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