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natita [175]
4 years ago
10

Evaluate a) sin (4pi/3) b) cos (5pi/6)

Mathematics
2 answers:
Karo-lina-s [1.5K]4 years ago
7 0
Sin(pi + a) = -sin(a)
sin(4pi/3) = sin(pi + pi/3) = -sin(pi/3)

cos(pi-a) = -cos(a)
cos(5pi/6) = cos(pi -pi/6) = -cos(pi/6)
kipiarov [429]4 years ago
3 0
A) sin ( 4π/3 ) = sin 240° = sin ( 180° + 60°) = - sin 60° = - \frac{ \sqrt{3} }{2}

b) cos (5π/6 ) = cos 150° = cos ( 90° + 60° ) = - sin 60°=- \frac{ \sqrt{3} }{2}
 
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