For this case we must follow the steps below:
step 1:
We place each of the given points on a coordinate axis
Step 2:
We join the AC points (represented by the orange line)
We join the BD points (represented by the blue line)
It is observed that the resulting figure after placing the 4 points on a coordinate axis, turns out to be a rhombus.
In addition, the blue and orange lines turn out to be perpendicular, that is, they have an angle of 90 degrees between them. This can be verified by finding the slopes of each of the two straight lines (blue and orange), which must be opposite reciprocal, that is, they comply: 
In this case, the slope of the orange line is 
and that of the blue line is 
Then 
, it is verified that they are perpendicular.
Thus, the conclusion is that ABCD is a rhombus and AC is perpendicular to BD.
Answer:
See attached image
Option D
Answer:
What is the question?
Step-by-step explanation:
Answer:
- x = 30°
- RS = 30°, SR = TU = 120°, UR = 90°
- ∠P = 45°
- ∠UTS = 60°
Step-by-step explanation:
(a) If RS = x, then the sum of arcs around the circle is ...
x + 4x +4x +3x = 360°
12x = 360°
x = 30°
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(b) Based on the given ratios, the arc measures are computed from x. For example, ST = TU = 4x = 4(30°) = 120°
- RS = 30°
- ST = 120°
- TU = 120°
- UR = 90°
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(c) Angle P is half the difference of arcs TU and RS:
∠P = (TU -RS)/2 = (120° -30°)/2
∠P = 45°
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(d) Inscribed angle UTS is half the measure of the arc it intercepts. Arc RU has the measure (30° +90°) = 120°, so the measure of UTS is ...
∠UTS = 120°/2 = 60°
Answer:
Resultant vector of two vectors is (0, 0).
Step-by-step explanation:
in this question two vectors having ordered pair (-6, 5) and (6, -5) have been given.
We can represent these vectors in the form of
and 
Now the resultant of these vectors will be = A + A'
A + A' = +
So the resultant vector = (0 + 0)
Therefore the resultant will be (0, 0)
The value of constant a is -5
Further explanation:
We will use the comparison of co-efficient method for finding the value of a
So,
Given
As it is given that
(x^2 - 3x + 4)(2x^2 +ax + 7) = 2x^4 -11x^3 +30x^2 -41x +28
In this case, co-efficient of variables will be equal, so we can compare the coefficients of x^3, x^2 or x
Comparing coefficient of x^3
So the value of constant a is -5
Keywords: Polynomials, factorization
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