The answer is: [D]: " 157" .
________________________________________________________
Explanation:
______________________________________________________
g(x) = 8x² + 9x − 7 ;
g(4) = 8(4²) + 9(4) <span>− 7 ;
</span>
= 8(4*4) + 36 <span>− 7 ;
</span>
= 8(16) + 36 <span>− 7 ;
</span>
= 128 + 36 <span>− 7 ;
</span>
= 164 − 7 ;
= <span>157 .</span>
_______________________________________________________
The answer is: [D]: " 157" .
_______________________________________________________
The answer is C: first add 2 both sides then divide both sides by -5.
Answer:
O A.
Step-by-step explanation:
<u>Option A</u> identifies two angles (sufficient for similarity) and one side, sufficient (with similarity) for congruence. The applicable congruence theorem is AAS.
<u>Option B</u> identifies two sides and the angle not between them. The two triangles will be congruent in that case only if the angle is opposite the longest side, which is <u>not true</u> in general.
<u>Option C</u> same deal as Option A.
<u>Option D</u> identifies three congruent angles, which will prove the triangles similar, but not necessarily congruent.
Answer:
-25
Step-by-step explanation:
g(f(3))= g(-5)
=4(-5)-5
= -20-5
=-25
Answer:
The probability that Scott will wash is 2.5
Step-by-step explanation:
Given
Let the events be: P = Purple and G = Green


Required
The probability of Scott washing the dishes
If Scott washes the dishes, then it means he picks two spoons of the same color handle.
So, we have to calculate the probability of picking the same handle. i.e.

This gives:










<em>Note that: 1 is subtracted because it is a probability without replacement</em>
So, we have:




