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Jobisdone [24]
3 years ago
12

Will give Brainliest!

Mathematics
1 answer:
Nataly [62]3 years ago
4 0
3.333 repeating is the answer :)
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Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. find the probability that
Kaylis [27]
<span>3/28 exactly, or approximately 10.7% Since we're drawing without replacement, let's first calculate the probability that the 1st marble is white. There are 3 white marbles out of a total of 8 marbles. So the probability of the 1st marble being white is 3/8. Now assuming that the first marble picked is white, the probability of the second marble is 2 out of the 7 remaining marbles. So it's probability is 2/7. This means that the probability of both marbles being white is 3/8 * 2/7 = 6/56 = 3/28, or approximately 10.7%</span>
5 0
3 years ago
A room is 20 feet long, 12 feet wide, and 10 feet high. What is the maximum distance from one corner to another
exis [7]

Answer:

25.38

Step-by-step explanation:

Its a 3-D block, so you have to find the distance from on corner to the opposite corner of the roof, but first find the distance from corner to corner on the floor.

20^2+12^2=c^2

400+144=544=c^2

c=\sqrt{544}

then find corner of floor to opposite roof corner.

100+544=644=c^2

c=\sqrt{644}

so its about 25.38 feet

4 0
3 years ago
Read 2 more answers
6 (2x - 7) + 4 (2x + 4)
Romashka [77]

Answer: 20x-26

Step-by-step explanation: its hard to explain

3 0
3 years ago
Read 2 more answers
For the level 3 course, exam hours cost twice as much as workshop hours, workshop hours cost twice as much as lecture hours. How
natulia [17]
<h2>Answer</h2>

Cost of lectures = $7.33 per hour

<h2>Explanation</h2>

Let e the cost of the exam hours

Let w be the cost of the workshop hours

Let l be the cost of the lecture hours.

We know from our problem that exam hours cost twice as much as workshop, so:

e=2w equation (1)

We also know that workshop hours cost twice as much as lecture hours, so:

w=2l equation (2)

Finally, we also know that 3hr exams 24hr workshops  and 12hr lectures cost $528, so:

3e+24w+12l=528 equation (1)

Now, lets find the value of l:

Step 1.  Solve for l in equation (3)

3e+24w+12l=528

12l=528-3e-24w equation (4)

Step 2. Replace equation (1) in equation (4) and simplify

12l=528-3e-24w

12l=528-3(2w)-24w

12l=528-6w-24w

12l=528-30w equation (5)

Step 3. Replace equation (2) in equation (5) and solve for l

12l=528-30w

12l=528-30(2l)

12l=528-60l

72l=528

l=\frac{528}{72}

l=\frac{22}{3}

l=7.33

Cost of lectures  = $7.33 per hour



3 0
3 years ago
Read 2 more answers
Please HELP ASAP thank you in advanced.....will give brianlest to best answer
11Alexandr11 [23.1K]

1st option, 2nd, 4th and 5th

5 0
3 years ago
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