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Kazeer [188]
3 years ago
8

Use models to show the sum of 120+205

Mathematics
2 answers:
maksim [4K]3 years ago
3 0

Answer:

Step-by-step explanation:

Vsevolod [243]3 years ago
3 0

Draw a bar and write 120 in it. Then make a bigger bar and write 205 in it. Finally, draw a bar the size of both of themand write 325 inside it.

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What is the solution to the system of equations graphed below? Pls Quick
leonid [27]
D- (-2,3) :)



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Pls answer the pic below
Mice21 [21]

Answer:

B. 6

Step-by-step explanation:

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5 0
3 years ago
Find the centroid for an area defined by the equations y = x² + 3 and y = - (x – 2)² + 7
meriva
The points where the 2 graphs intersect is  where x = 0 and x = 2.

-                 2                                  2
x   =    INT               x dA     /    INT        dA
                  0                                  0

INT dA   = INT -x^2 + 4x + 3 - (x^2 + 3 ) dx  =      INT -2x^2  + 4x
               =   -2 x^3/3 + 2x^2
               =   2.667  between 0 and 2

xdA  =   -2x^3 + 4x^2  INT xdA  =   -x^4/2 + 4x^3/3 = 2.667

centroid = 2.667 / 2.667  = 1  (x = 1)
3 0
3 years ago
Read 2 more answers
Daniel is printing out copies of a presentation. It takes 3 minutes to print a color copy and 1 minute to print a black-and-whit
Effectus [21]
Work the information to set inequalities that represent each condition or restriction.

2) Name the variables. 

c: number of color copies
b: number of black-and-white copies

3) Model each restriction:

i) <span>It takes 3 minutes to print a color copy and 1 minute to print a black-and-white copy.
</span><span>
</span><span>3c + b
</span><span>
</span><span>
</span><span>ii) He needs to print at least 6 copies ⇒ c + b ≥ 6
</span><span>
</span><span>
</span><span>iv) And must have the copies completed in no more than 12 minutes ⇒</span>

3c + b ≤ 12
<span />

4) Additional restrictions are c ≥ 0, and b ≥ 0 (i.e. only positive values for the number of each kind of copies are acceptable)

5) This is how you graph that:

i) 3c + b ≤ 12: draw the line 3c + b = 12 and shade the region up and to the right of the line.

ii) c + b ≥ 6: draw the line c + b = 6 and shade the region down and to the left of the line.

iii) since c ≥ 0 and b ≥ 0, the region is in the first quadrant.

iv) The final region is the intersection of the above mentioned shaded regions.

v) You can see such graph in the attached figure.

6 0
3 years ago
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