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2 years ago

Write three million five hundred twenty six thousand two hundred forty five in standard form

2 answers:

7 0

Standard form: 3,526,245

Expanded form: 3,000,000 + 500,000 + 20,000 + 6,000 + 200 + 40 + 5

You've already written it in word form :)

Hope this helps!

Temka [501]2 years ago

3 0

3,526,245 is the answer.

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Write a real-world problem involving a percent that can be solved by using the proportion 3/b= 60/100. Then solve the proportion

inessss [21]

Dax goes to the store to buy milk. There is a sale for milk, and it now costs 3 dollars since it was 60% off. What was the original price of the milk?
3 - 60
x - 100
Cross multiply
300=60x
5=x

The milk original cost 5 dollars.

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2 years ago

Numbers expressed using exponents are called

dangina [55]

Numbers expressed using exponents are called base :)

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3 years ago

07.03 LC)

Inga [223]

$Q1.\\p\%=\dfrac{p}{100};\ 20\%=\dfrac{20}{100}=0.20=0.2\\\\20\%-French\ of\ 500\ people\\\\0.2\cdot500=100\leftarrow Answer$

$Q2.\\\dfrac{white}{all}\cdot\dfrac{yellow}{all-1}\\\\7+8+9=24-number\ of\ all\ roses\\\\\dfrac{9}{24}\cdot\dfrac{8}{24-1}=\dfrac{9}{24}\cdot\dfrac{8}{23}=\dfrac{72}{552}\leftarrow Answer$

$Q3.\\5-number\ of\ 2\\100-number\ of\ all\\\\\dfrac{5}{100}\leftarrow Answer$

$Q4.\\1+5+10=16-number\ of\ all\ marbles\\\\\dfrac{10}{16}\cdot\dfrac{10-1}{16-1}=\dfrac{10}{16}\cdot\dfrac{9}{15}\leftarrow Answer$

4 0

2 years ago

Read 2 more answers

What is the answer please.... need help

mina [271]

Answer:

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

$f\left(x\right)=x^3-6x^2+3x+10$

As the highest power of the x-variable is 3 with the leading coefficients of 1.

So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

$f\left(x\right)=x^3-6x^2+3x+10$

$0=x^3-6x^2+3x+10$ ∵ $f(x)=0$

$Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

$\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

Using the zero factor principle

if $ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0$

$x=-1,\:x=2,\:x=5$

Therefore, the zeros of the function are:

$x=-1,\:x=2,\:x=5$

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.

8 0

2 years ago

Line t passes through points (10, 1) and (2, 6). Line u is perpendicular to t. What is the slope of line u?

diamong [38]

Let's find the slope for line t first.

We can use the given points 2,6 and 10,1 to find the slope using the slope formula.

$\frac{y.2 - y.1}{x.2 - x.1} = m$

1 - 6 / 10 - 2

-5/8

The slope is -5/8.

Because we know the slope of this line, we can find the slope of the next line instantly, as they are perpendicular.

When a slope is perpendicular to another, it is equal to the negative reciprocal.

Negative reciprocal of -5/8 = 8/5

<h3>The slope of line u is 8/5</h3>

8 0

2 years ago