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lara [203]
3 years ago
14

A toy company can spend no more than $2,000 on raw materials for plastic trains and metal trains. The raw materials cost $0.80 p

er pound for metal and $0.40 per pound for plastic. To summarize the situation, a worker writes the inequality: 0.8m + 0.4p ≤ 2,000, where m is the number of pounds of metal material and p is the number of pounds of plastic material. Which graph's shaded region shows the possible combinations of raw materials the company can buy?

Mathematics
1 answer:
Goryan [66]3 years ago
6 0

Answer:

<em>The gaph is shown in the image below</em>

Step-by-step explanation:

<u>Graph of Inequalities</u>

Let's graph the region of the inequality

0.8m + 0.4p \leq 2,000

Since there is no indication, we'll assume the variable p to be in the horizontal axis and m in the vertical axis. Let's solve for m

\displaystyle m=\frac{2,000-0.4p}{0.8}

Since both m and p are positive, we can assume

2,000-0.4p\geq 0

Or, equivalently

p \leq 5,000

Thus, we can give p any value between 0 and 5,000 to get the corresponding values for m. Let's select the values p=0, p=1,000, p=5,000 to get the points

( 0 ; 2,500 ) ( 1,000 ; 2,000 ) ( 5,000 ; 0 )

With these points we can plot the line representing the function. To know which area must be shaded, we only need to test one point below or above the line. If it fulfills the inequality, then the whole area is shaded.

Let's test the point ( 1,000 ; 1,000 )

0.8\cdot 1,000 + 0.4\cdot 1,000 \leq 2,000

1,200 \leq 2,000

Since the condition is met, the area below the line must be shaded as the solution of the inequality

The gaph is shown in the image below

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Answer:

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b) the probability is 0.7382 (73.82%)

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Step-by-step explanation:

Since each box is independent of the others and defining the random variable X= number of boxes of cereal purchased without prices until having 2 prices , then X has a negative binomial distribution . Thus

P(X=k)= C(k+r-1,k)*p^k *(1-p)^r

where

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P(X=k) = probability of purchasing k boxes without prices until obtaining r boxes with prices

a) for k= 8 - r = 6

P(X=6)= C(7,6)*0.8^6*0.2^2 = 7*0.8^6*0.2^2 = 0.0734 (7.34%)

b) for k≥9-2=7

P(X≥7) = 1- P(X<7)= 1- Fn(X=7)

where Fn(X) is the cumulative negative binomial distribution. We can calculate it through its relationship with the cumulative binomial distribution Fb(X) that is easily found in tables :

Fn(k=7,r=2,p=0.8) = Fb(k=7,n=k+r=9,p=0.8) = 0.2618

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P(X≥7) = 1- P(X<7)= 1- Fn(X=7) = 1-  0.2618 = 0.7382 (73.82%)

c) the expected value E(X) for a negative binomial distribution is

E(X)= p*r/(1-p) = 0.8*2/0.2 = 8 boxes that do not contain prices

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Answer:

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