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lara [203]
3 years ago
14

A toy company can spend no more than $2,000 on raw materials for plastic trains and metal trains. The raw materials cost $0.80 p

er pound for metal and $0.40 per pound for plastic. To summarize the situation, a worker writes the inequality: 0.8m + 0.4p ≤ 2,000, where m is the number of pounds of metal material and p is the number of pounds of plastic material. Which graph's shaded region shows the possible combinations of raw materials the company can buy?

Mathematics
1 answer:
Goryan [66]3 years ago
6 0

Answer:

<em>The gaph is shown in the image below</em>

Step-by-step explanation:

<u>Graph of Inequalities</u>

Let's graph the region of the inequality

0.8m + 0.4p \leq 2,000

Since there is no indication, we'll assume the variable p to be in the horizontal axis and m in the vertical axis. Let's solve for m

\displaystyle m=\frac{2,000-0.4p}{0.8}

Since both m and p are positive, we can assume

2,000-0.4p\geq 0

Or, equivalently

p \leq 5,000

Thus, we can give p any value between 0 and 5,000 to get the corresponding values for m. Let's select the values p=0, p=1,000, p=5,000 to get the points

( 0 ; 2,500 ) ( 1,000 ; 2,000 ) ( 5,000 ; 0 )

With these points we can plot the line representing the function. To know which area must be shaded, we only need to test one point below or above the line. If it fulfills the inequality, then the whole area is shaded.

Let's test the point ( 1,000 ; 1,000 )

0.8\cdot 1,000 + 0.4\cdot 1,000 \leq 2,000

1,200 \leq 2,000

Since the condition is met, the area below the line must be shaded as the solution of the inequality

The gaph is shown in the image below

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Answer:

Taking data:

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Step-by-step explanation:

As the data is not given in the question i'm guessing the data from the question i solved before

28 78 74 89 72

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as taking the above data,

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As we know for finding the width of class:

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Note : By using the above given formula you can calculate the width of any data just by taking the maximum and minimum values of data and the number of classes the data is divided into.

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