Answer:
2x - 4 < y < -3x + 3
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Answer:
JL ≈ 32
Step-by-step explanation:
The triangle JKL has a side of JK = 24 and we are asked to find side JL. The triangle JKL is a right angle triangle.
Let us find side the angle J first from the triangle JKM. Angle JMN is 90°(angle on a straight line).
using the cosine ratio
cos J = adjacent/hypotenuse
cos J = 18/24
cos J = 0.75
J = cos⁻¹ 0.75
J = 41.4096221093
J ≈ 41.41°
Let us find the third angle L of the triangle JKL .Sum of angle in a triangle = 180°. Therefore, 180 - 41.41 - 90 = 48.59
Angle L = 48.59
°.
Using sine ratio
sin 48.59
° = opposite/hypotenuse
sin 48.59
° = 24/JL
cross multiply
JL sin 48.59
° = 24
divide both sides by sin 48.59
°
JL = 24/sin 48.59
°
JL = 24/0.74999563751
JL = 32.0001861339
JL ≈ 32
30 minutes. the easiest way is to use the opposite of the fraction. divide 25 / 5= 5. now multiply by 6. 5*6= 30.
Answer:
if two parallel lines are cut by a transversal so that the alternate interior angles are <u>congruent,</u> then the lines are parallel.
