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Tomtit [17]
3 years ago
9

Relationship B has a lesser rate than Relationship A. This graph represents Relationship A.Which equations could represent Relat

ionship B? Select each correct answer. y = xy = 5xy = 4xy=32xFirst-quadrant graph showing a ray from the origin through the points begin ordered pair 1, 3 ends ordered pair and begin ordered pair 2, 6 ends ordered a pair.

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
3 0
<h3>Answer:</h3>
  • y = x
  • y = (3/2)x
<h3>Explanation:</h3>

The rate shown in your graph is 3. (rise:run = 3:1) An equation with a lesser rate will have an x-coefficient that is less than 3. The x-coefficients in your answer choices appear to be ...

  • 1
  • 5
  • 4
  • 3/2

Of these values, only the first and last are less than 3.

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John has $220 in his account and adds $25 to it each month Cheryl has $100 in her account and adds $35 each to her account. How
sammy [17]

Answer: In 12 months they will have the same amount, which will be $520.

Step-by-step explanation:

220 + 25m = 100 + 35m

m = month

Subtract 100 from each side

120 + 25m = 35m

Subtract 25m from each side

120 = 10m

Divide each side by 10

12 = m

4 0
3 years ago
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Xelga [282]

Answer:

<u>18.8%</u>

Step-by-step explanation:

For calculating this, focus on one part of the table :

  • The row where students do not like sandwiches

There are 32 students who do not like sandwiches, and 6 of them do not like pies. Take this a proportion :

  • P (does not like pies, do not like sandwiches) = 6/32
  • P = 3/16
  • P = <u>18.8%</u>
7 0
2 years ago
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Which expression iWhich expression is equivalent to x + 8 + 4x + 2x for all values of x?s equivalent to x + 8 + 4x + 2x for all
NikAS [45]

Answer:

A = l * w. We can substitute the expressions for length and width into the equation for area ... values in the formula for perimeter, we will get. P = 2l + 2w. P = 2(5)+2(3) P = 10+6 ... L = 18 cm. B = 7 cm. Perimeter of rectangle = 2(length + breadth) P = 2 (L + B) ... Total time taken = Total distance walked × time taken to walk 1m.

4 0
2 years ago
Criterion: Identify IV, DV, and hypotheses and evaluate the null hypothesis for an independent samples t test. Data: Use the inf
Papessa [141]

The table is missing in the question. The table is provided here :

Group 1        Group 2

 34.86            64.14      mean

 21.99            20.46      standard deviation

  7                    7                n

Solution :

a). The IV or independent variable = Group 1

    The DV or the dependent variable = Group 2

b).

  $H_0: \mu_1 = \mu_2$

  $H_a:\mu_1 < \mu_2$

  Therefore,   $t = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{s_1^2}{n_1}+\frac{S_2^2}{n_2}}}$

$t = \frac{34.86 - 64.14}{\sqrt{\frac{21.99^2}{7}+\frac{20.46^2}{7}}}$

t = -2.579143

Now,   $df = min(n_1 - 1, n_2 - 1)$

           df = 7 - 1

               = 6

Therefore the value of p :

  $=T.DIST(-2.579143,6,TRUE)$

 = 0.020908803

The p value is 0.0209

$p< 0.05$

So we reject the null hypothesis and conclude that $\mu_1 < \mu_2$

7 0
3 years ago
why write a quadratic function whose graph has the given characteristics vertex :(2,3) point on graph (0,-1)
GaryK [48]
<h3>Answer:</h3>

f(x) = -(x -2)² +3

<h3>Step-by-step explanation:</h3>

We can fill in the vertex (h, k) values immediately in the vertex form ...

... f(x) = a(x -h)² +k

To find the value of a, we solve the equation for a at some point other than the vertex. The given point is (0, -1), so we can use that:

... -1 = a(0 -2)² +3

... -4 = 4a . . . . . . . . . subtract 3, simplify

... -1 = a . . . . . . . . . . . divide by 4

Now, we know the function is ...

... f(x) = -(x -2)² +3

5 0
3 years ago
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