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Art [367]
3 years ago
11

Create and evaluate an expression that shows "the quotient of eight raised to the power of two and four, decreased by six."

Mathematics
1 answer:
AnnyKZ [126]3 years ago
5 0

((8^2)/4)-6 = (64/4)-6 = 16-6 = 10
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Help help help if u can answer this I’ll mark u brainliest (6) (the one in the middle)
Hoochie [10]

You just have to plug in each thing:

So f(0):

3(0)^2 - 4 = -4

so its not A

f(-2) and f(2):

3(-2)^2 - 4

3(2)^2 -4

now we don't even have to calculate these, anything to the power of an even number is a positive number so -2^2 and 2^2 both equal 4

B is correct, so you can do the others if you want to check, but if B is true the others shouldn't be true.

4 0
4 years ago
Hatah and his 3 friends are each running an equal part of a la mile race.
Lana71 [14]

Answer:3.5 miles

Step-by-step explanation:

8 0
3 years ago
Please write the answer​
Travka [436]

\sf \dfrac{3^x - 5 \times 3^{(x-2)}}{3^{(x-3)}} \\ \\ \longrightarrow \sf \dfrac{ {3}^{x} }{ {3}^{(x - 3)}} - \frac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)}  \\ \\ \longrightarrow \sf {3}^{[x - (x - 3)]} - \dfrac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ {3}^{(x - 3)} } \times \dfrac{ {3}^{x}}{9} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ \bigg(\dfrac{ {3}^{x} }{ {3}^{3} }\bigg) } \times \dfrac{ {3}^{x}}{9}\\ \\ \longrightarrow \sf {3}^{3} - \dfrac{ ({3}^{3})( 5)}{ {3}^{x} } \times \dfrac{ {3}^{x}}{9}\\ \\ \sf \longrightarrow {3}^{3} - (5 \times 3) \\  \\ \longrightarrow \sf \: 27 - 15 \\  \\ \longrightarrow \leadsto{\underline{\boxed{\sf{ \pink{ 12}}}}}

6 0
2 years ago
What is (f⋅g)(x)? Enter your answer in the box.
igor_vitrenko [27]
(f*g)(x)=(x³-4x+2)(x²+2) = x⁵+2x³-4x³-8x+2x²+4=x⁵-2x³+2x²-8x+4
6 0
3 years ago
Simplify. 5 - [ - ( - 2)]
Nimfa-mama [501]

Answer:

3

Step-by-step explanation:

1. A - times a - equals a +, which means [-(-2)] equals (2)

2. 5- (2) equals 5 - 2

3. 5-2= 3

6 0
3 years ago
Read 2 more answers
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