Create and evaluate an expression that shows "the quotient of eight raised to the power of two and four, decreased by six."

Mathematics

1 answer:

AnnyKZ [126]3 years ago

5 0

((8^2)/4)-6 = (64/4)-6 = 16-6 = 10

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Help help help if u can answer this I’ll mark u brainliest (6) (the one in the middle)

Hoochie [10]

You just have to plug in each thing:

So f(0):

3(0)^2 - 4 = -4

so its not A

f(-2) and f(2):

3(-2)^2 - 4

3(2)^2 -4

now we don't even have to calculate these, anything to the power of an even number is a positive number so -2^2 and 2^2 both equal 4

B is correct, so you can do the others if you want to check, but if B is true the others shouldn't be true.

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4 years ago

Hatah and his 3 friends are each running an equal part of a la mile race.

Lana71 [14]

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Step-by-step explanation:

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3 years ago

Please write the answer

Travka [436]

$\sf \dfrac{3^x - 5 \times 3^{(x-2)}}{3^{(x-3)}} \\ \\ \longrightarrow \sf \dfrac{ {3}^{x} }{ {3}^{(x - 3)}} - \frac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)} \\ \\ \longrightarrow \sf {3}^{[x - (x - 3)]} - \dfrac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ {3}^{(x - 3)} } \times \dfrac{ {3}^{x}}{9} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ \bigg(\dfrac{ {3}^{x} }{ {3}^{3} }\bigg) } \times \dfrac{ {3}^{x}}{9}\\ \\ \longrightarrow \sf {3}^{3} - \dfrac{ ({3}^{3})( 5)}{ {3}^{x} } \times \dfrac{ {3}^{x}}{9}\\ \\ \sf \longrightarrow {3}^{3} - (5 \times 3) \\ \\ \longrightarrow \sf \: 27 - 15 \\ \\ \longrightarrow \leadsto{\underline{\boxed{\sf{ \pink{ 12}}}}}$