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3 years ago

Which of the transformations below CANNOT be used to create an image that is congruent

1 answer:

7 0

Rotation,reflections,and translations are isometric. That means that these transformations do not change the size of the figure. If the size and shape of the figure is not changed, then the figures are congruent.

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The sum of the ages of Mr Lin and his son Ethan is 38 years. In three years' time, Mr Lin will be three times as old as his son.

Sati [7]

Answer:

Mr.Lin's present age is 30 years now. His son is 8 years old now.

Step-by-step explanation:

Let L = Mr.Lin's present age,

S = his son's present age.

First equation is

L + S = 38. (1)

The second equation is

L + 3 = 3*(S+3) (2) ("In three years' time, Mr.Lin will be three times as old as his son.")

From (1), express S = 38-L and substitute it into (2). You will get

L + 3 = 3*((38-L)+3), or

L + 3 = 114 - 3L + 9,

4L = 114 + 9 - 3,

4L = 120,

L = 30.

8 0

3 years ago

A blue die and a red die are thrown. B is the event that the blue comes up with a 6. E is the event that both dice come up even.

iVinArrow [24]

Answer:

Size of |E n B| = 2

Size of |B| = 1

Step-by-step explanation:

I'll assume both die are 6 sides

Given

Blue die and Red Die

Required

Sizes of sets

- $|E\ n\ B|$

- $|B|$

The question stated the following;

B = Event that blue die comes up with 6

E = Event that both dice come even

So first; we'll list out the sample space of both events

$B = \{6\}$

$E = \{2,4,6\}$

Calculating the size of |E n B|

$|E n B| = \{2,4,6\}\ n\ \{6\}$

$|E n B| = \{2,4,6\}$

The size = 3 because it contains 3 possible outcomes

Calculating the size of |B|

$B = \{6\}$

The size = 1 because it contains 1 possible outcome

8 0

3 years ago

If f(x) is a fifth degree polynomial, is it possible that it has exactly 5 complex roots?

Zolol [24]

No.

A fifth degree polynomial, having a graph that increases and starts from below x-axis.

Therefore, no matter what equation it is. The fifth degree polynomial will intercept x-axis AT LEAST one.

The fifth degree polynomial can have only at maximum, 4 complex roots.

You can try drawing or seeing the graph of fifth-degree polynomial function. No matter what equations, they still intercept at least one x-value.

4 0

3 years ago

Please help:) I'll report you if you steal points :(

Crank

Yeah y=9

hope this helped even tho I’m kinda late haha

5 0

2 years ago

Find the point on the line y = 2x + 3 that is closest to the origin.

ch4aika [34]

1)We have to make a line perpendicular to y=2x+3, passing through the point (0,0).

y=2x+3
m=solpe=2

The slope of the line perpedicular to y=2x+3 is m´
m´=-1/m
m´=-1/2

Point slope form:
y-y₀=m(x-x₀)
(0,0)
m=-1/2

y-0=-1/2(x-0)
y=-x/2

Therefore, the line perpendicular to y=2x+3 is y=-x/2.

2)The point on the line y=2x+3 tha is closest to the origin is the point of intersection of the two lines.

y=2x+3
y=-x/2

We can solve this system of equations by equalization method.
2x+3=-x/2
least common multiple=2
4x+6=-x
4x+x=-6
5x=-6
x=-6/5 (=-1.2)

y=-x/2
y=-(-6/5)/2=6/10=3/5 (=0,6)

Therefore: the point of the line y=2x+3 that is closest to the origin is:
(-1.2 , 0.6)

3 0

3 years ago