Answer:
see attachment
Step-by-step explanation:
The directions tell you what you need to know. It is a matter of adding up the values shown and finding the missing number to make the total be -20. Of course, it works best to start with a row, column, or diagonal that has 4 numbers already.Then, you're only finding the 5th number.
You can start with either diagonal, column 1 or 4, and row 4 or 5. Filling the missing numbers in those spots (red) will let you find the remaining missing numbers (green, then blue).
The square at row 2, column 2 can be filled on the first round using the down-right diagonal. I have shown it as filled on the second round after row 5 column 2 is filled.
Using a spreadsheet can make this easier, because you can write formulas for the sums in each row, column, and diagonal. Then you're just making those sums be -20.
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For example, consider the up-right diagonal. The sum of the given values, -6, 0, -4, -2, is -12. Then the spot at row 1, column 5 must be filled with -8 to make the sum be -20.
Answer:
Step-by-step explanation:
A quadratic equation can be factorised if and only if there are rational roots.
For any quadratic equation the discriminant decides about the nature of roots.
Thus only if the discriminant is a perfect square we can have rational roots and in this case only factorization is possible.
In the given equation
Since 1 is a perfect square we can factor and solve
9514 1404 393
Answer:
Step-by-step explanation:
All of these exponential function problems use the same equation, but with different plug-in values. These can be easily accommodated by a spreadsheet or graphing calculator.
The general form of the value after t years is ...
(initial value)×(1 +annual growth rate)^(years)
The growth rate is positive for an increase, negative for a decrease.
a) Initial value: 22385; growth rate: -0.14; years: 10
value after 10 years: $22385×(1-0.14)^10 = $4953.84
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b) initial value: 290; growth rate: 0.09; years: 5
population after 5 years: 290(1+.09)^5 = 446
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c) initial value: $4000; growth rate: -0.10; years: 8
value after 8 years: $4000(1 -0.10)^8 = $1721.86
Selling the car for $1500 is selling it for <em>less than its estimated value</em>. That may not be a good decision.
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<em>Additional comment</em>
The property value of the car is not the only consideration when evaluating the sale. Other costs related to the car may come into play, and there may be tax implications.
