Hello!
This equation is written in Point-Slope Form (y-y₁=m(x-x₁)
Where
y₁=y-coordinate of the point
m=slope
x₁=x-coordinate of the point
In this case, the slope is
Hope everything is clear.
Let me know if you have any questions!
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X + 5y = 14
5y = -x + 14
y = -1/5x + 14/5.....the slope here is -1/5. A perpendicular line will have a negative reciprocal slope. All that means is flip the slope and change the sign. So our perpendicular slope will be 5. See how I flipped -1/5 making it -5/1...and then changed the sign, making it 5.
y = mx + b
slope(m) = 5
(-5,-2)....x = -5 and y = -2
now we sub and find b, the y int
-2 = 5(-5) + b
-2 = -25 + b
-2 + 25 = b
23 = b
so ur perpendicular equation is : y = 5x + 23 <==
The answer should be x=4/3
