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Tpy6a [65]
3 years ago
5

I need it ASAP please

Mathematics
1 answer:
Paraphin [41]3 years ago
5 0
Look at my picture for the work

Answer: a=8 and b=2

Please let me know if this helped!!

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two groups of friends are sharing apples of the same size. The first group of 3 friends share 4 apples. The second group of 4 fr
nikdorinn [45]

Answer:

The second group

Step-by-step explanation:

The first group is 4 apples for 3 friends.

= 4/3. They each got 1 & 1/3 of an apple.

The second group is 6 apples for 4 friends.

= 6/4. They each got 1 & 1/2 of an apple.

1 1/3 < 1 1/2, so friends in the second group get a larger portion of apples

3 0
3 years ago
How do you do this?
lora16 [44]
X/5 = 24/8
  (because the triangles are similar)

x/5 = 3

x = 5*3 = 15 Answer

a/27 = 8/24 = 1/3 
a =  9  Answer
6 0
3 years ago
Read 2 more answers
A bank features a savings account that has an annual percentage rate of 3.5% with interest compounded quarterly. Vanessa deposit
vazorg [7]

Answer:

APY = 0.04 or 4%

Step-by-step explanation:

Given the annual percentage rate of 3.5% that is compounded quarterly, and a principal of $6,500:

We can use the following formula to solve for the annual percentage yield (APY):

APY =  (1 + \frac{r}{n})^n - 1

where <em>r</em> = interest rate = 3.5% or 0.035

<em>           n</em> = number of compounding periods per year = 4

We can plug in the values into the equation:

APY =  (1 + \frac{r}{n})^n - 1

APY =  (1 + \frac{.035}{4})^4 - 1

APY =  (1 + 0.00875)^4 - 1

APY =  (1.00875)^4 - 1

APY = 1.03546 - 1  

APY = 0.04 or 4%        

8 0
3 years ago
15 plus the difference of 10 and a number X is 15 (X=?)
Verizon [17]
15+(10-x)=15 would be your equation if that is what you are looking for.
5 0
3 years ago
A small business assumes that the demand function for one of its new products can be modeled by p = Cekx. When p = $40, x = 1000
Maru [420]

Answer:

C= 82.1116

k=-0.0007192

Step-by-step explanation:

p=Ce^{kx}\\40=Ce^{k1000}\\30=Ce^{k1400}\\

Applying logarithmic properties yields in the following linear system:

ln(40) = ln(C) + 1000k\\ln(30) = ln(C) + 1400k

Solving for k:

ln(40) = ln(C) + 1000k\\ln(30) = ln(C) + 1400k\\400 k = ln(30)-ln(40)\\k=-0.0007192

Solving for C:

40=Ce^{-0.0007192*1000}\\C= \frac{40}{e^{-0.0007192*1000}}\\C=82.1116

C= 82.1116

k=-0.0007192

6 0
3 years ago
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