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Lubov Fominskaja [6]
3 years ago
5

C. Directions: Copy and answer. Write in the circle the final sum of

Mathematics
1 answer:
prisoha [69]3 years ago
6 0

Answer:

98

Step-by-step explanation:

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A sign company charges $28 per yard for each custom-made banner. Ms.Gill orders two banners that are each 178 yards long, and on
zhuklara [117]

Given,

A sign company charges $28 per yard for each custom-made banner.

Ms.Gill orders two banners that are each 178 yards long, and one banner that is 258 yards long.

To find,

Total money paid by Ms. Gill.

Solution,

Total length of 2 banners of 178 yards = 356 yards

Third banner is 258 yards long.

Total length of the banners = 356 + 258

= 614 yards

The cost of each banner = $28 per yards.

Total amount paid by Ms. Gill is :

= $28 × 614

= $17,192

Hence, she will pay $17,192 for all the three banners.

8 0
3 years ago
What is the power of 256
Juli2301 [7.4K]

In mathematics. 256 is a composite number, with the factorization 256 = 28, which makes it a power of two. 256 is 4 raised to the 4th power, so in tetration notation 256 is 24.

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4 years ago
Please help me I will name you the brainliest!!! Plus you get 20 points!!!
viva [34]

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Step-by-step explanation: x-3 will move 3 to left y + 1 will move up 1

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3 years ago
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ruslelena [56]

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2 years ago
A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 2 of 2 :
const2013 [10]

Answer:

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective.

This means that n = 1067, \pi = \frac{74}{1067} = 0.069

80% confidence level

So \alpha = 0.2, z is the value of Z that has a pvalue of 1 - \frac{0.2}{2} = 0.9, so Z = 1.28.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 - 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.059

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 + 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.079

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

7 0
3 years ago
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