The value of <em>a</em> and <em>b</em> for the data values of stalk of corn using the logarithmic regression is -76.2038 and 37.6735 respectively.
<h3>What is logarithmic regression?</h3>
Logarithmic regression is a type of regression which is used to model the statement in which the growth or decay initially at rapid rate, and then slow down with respect to time.
The data of the table for the day and height of the stalk of corn is listed below.
Day (<em>x</em>) 9 12 22 40
Height (<em>y</em>) in 5 17 45 60
Mean of x values,

Mean of y values,

For the above table, the value of correlation coefficient is 0.99133. For these values, the logarithmic regression can be given as,

Compare it with the following logarithmic regression equation, we get


Hence, the value of <em>a</em> and <em>b</em> for the data values of stalk of corn using the logarithmic regression is -76.2038 and 37.6735 respectively.
Learn more about the logarithmic regression here;
brainly.com/question/25226042
Answer:
- 6 2/3 qt 80%
- 13 1/3 qt 20%
Step-by-step explanation:
It is often convenient to solve a mixture problem by letting a variable represent the quantity of the higher-concentration contributor to the mix.
__
We can let x represent the number of quarts of 80% solution needed. Then (20-x) is the number of quarts of 20% solution needed. The amount of salt in the final mix is ...
0.80x +0.20(20-x) = 0.40(20)
0.60x = 0.20(20) . . . . . . . . subtract 0.20(20) and simplify
x = 20/3 = 6 2/3 . . . . . . . . . divide by 0.60; quarts of 80% solution
(20 -x) = 13 1/3 . . . . . . . . . . amount of 20% solution needed
The teacher should mix 6 2/3 quarts of 80% solution with 13 1/3 quarts of 20% solution.
37.5 % of 800 is 300 because of division
In short the answer is 5/25 or 1/5 either works.

Solve for x by cross multiplication


- Swap the sides of equation

- Divide both sides of equation by 30
