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blsea [12.9K]
3 years ago
14

An exam consists of 15 true-or-false questions. If a student guesses at every answer, what is the probability that he or she wil

l answer exactly 9 questions correctly? (Round your answer to three decimal places.).
Mathematics
1 answer:
Bas_tet [7]3 years ago
4 0
<span>C(15,9) * (1/2)^9 * (1/2)^6 = 5005/32768 = .153 approx</span>
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⅜ of the animals at the zoo equals to 600. 40% of all the animals at the
raketka [301]

Answer:

960

Step-by-step explanation:

3/8*total number of animals = 600

total number of animals = 8/3 * 600 = 1600

number of animals fed = 40/100 * 1600 = 640

animals still to be fed = 1600 - 640 = 960

5 0
2 years ago
Select The decimal that is equivalent to 7/8
tatuchka [14]

Answer:

0.875

Step-by-step explanation:

look at the fraction as a division problem

8÷7

8 0
2 years ago
Jeff gave 1/4 of a sum of money to his wife. Then he divided the remainder equally among his 4 children.
Semenov [28]

Answer:

A) The fraction of sum of money did each child receive is \frac{3 x}{16}

B) The sum of money did Jeff have $ 3200

Step-by-step explanation:

Given as :

Let The sum of money did Jeff have = $ x

The fraction of money did Jeff's wife get = \frac{1}{4} of $ x

The remaining money Jeff will have = $ x - \frac{1}{4} of $ x

I.e The remaining money Jeff will have = \frac{4 x - x}{4}

                                                                = \frac{3 x}{4}

A ) The remaining amount of money is divided equally among 4 children

So, The fraction of sum of money did each child receive = \frac{\frac{3 x}{4}}{4}

I.e The fraction of sum of money did each child receive =  \frac{3 x}{16}

B ) If each child will receive $ 600

∴,  \frac{3 x}{16} = $ 600

Or, 3 x = $ 600 × 16

Or, 3 x = $ 9600

∴    x = \frac{9600}{3}

I.e  x = $ 3200

So, The sum of money did Jeff have $ 3200  

Hence ,

A) The fraction of sum of money did each child receive is \frac{3 x}{16}

B) The sum of money did Jeff have $ 3200   Answer

8 0
3 years ago
If a=2b^3 and b= -1/2c ^-2,express a in terms of c.
ElenaW [278]

Answer:

Part 1) a=-\frac{1}{4c^6}

Part 2) a=-\frac{1}{4c^{-6}}

Step-by-step explanation:

Part 1) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2}c^{-2} ----> equation B

substitute equation B in equation A

a=2(-\frac{1}{2}c^{-2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}

therefore

a=-\frac{1}{4c^6}

Part 2) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2} ----> equation B

substitute equation B in equation A

a=2(-\frac{c^{2}}{2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})

simplify

a=-\frac{c^{6}}{4}

therefore

a=-\frac{1}{4c^{-6}}

6 0
3 years ago
A plane loses altitude at the rate of 5 meters per second. It begins with an altitude of
Katarina [22]

Answer:

ffhdfhfgfghgfhg

Step-by-step explanation:

8 0
3 years ago
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