Since x & y vary directly (it means when x increases, y increases & vice versa)
Then the equation==> y = k.x (k is a constant to be calculated)
But x=4 and y= (given) ==> 2=4k or k= 1/2 & the equation becomes <span>y=1/2 (x)</span>
Answer:
The approximate length of the diagonal walkway is 21.21 meters
Step-by-step explanation:
we know that
Applying the Pythagorean Theorem in the square park, find out the the approximate length of the diagonal walkway
so
![c^2=a^2+b^2](https://tex.z-dn.net/?f=c%5E2%3Da%5E2%2Bb%5E2)
where
c is the diagonal of the square
a and b are the length sides of the square
we have
![a=15\ m\\b=15\ m](https://tex.z-dn.net/?f=a%3D15%5C%20m%5C%5Cb%3D15%5C%20m)
substitute
![c^2=15^2+15^2\\c^2=450\\c=21.21\ m](https://tex.z-dn.net/?f=c%5E2%3D15%5E2%2B15%5E2%5C%5Cc%5E2%3D450%5C%5Cc%3D21.21%5C%20m)
therefore
The approximate length of the diagonal walkway is 21.21 meters
In order to triple this you have to put 3 in fraction form (3/1, 3 because triple is 3). 4/3 x 3/1 equals 12/5. <u>If you are required to simply then the answer would be </u><u>2, 2/5</u><u>. </u>
Answer:
6
Step-by-step explanation:
x, or the amount of days is the independent variable.