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svetlana [45]
4 years ago
7

Raul has 50 coupon books to sell. he must sell at least 10 coupon books to win a prize. the amount of money raul makes from sell

ing x coupon books is represented by a function. f(x)=20xf(x)=20x what is the practical domain of the function? all integers from 10 to 50, inclusive all multiples of 20 between 0 and 1000, inclusive all real numbers all integers from 0 to 50, inclusive
Mathematics
1 answer:
Lana71 [14]4 years ago
6 0
I believe that the answer is: A all integers from 10 to 50 , inclusive
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Solve the equation by taking the square root 4(x+1)^2=100
Naddika [18.5K]

Answer:

Step-by-step explanation:

4(x+1)²=100

(x+1)²= 5²

(x+1)²- 5² = 0

(x+1-5)(x+1+5) = 0  by identity : a² - b ² = (a - b) (a+b)

(x - 4 ) (x+6) =0

x - 4 = 0 or x+6 = 0

x = 4  or x = - 6

3 0
3 years ago
Your friend rolls a number cube 500 times. How many times do you think your friend will roll an odd number? Explain your reasoni
VladimirAG [237]
250, because of probability. Half of the number are full of odd numbers. Half are full of even. The probability will be 1/2. So 1/2 of 500 is 250. So your answer is 250 times.
5 0
4 years ago
[PLEASE BE QUICK] Write the equation of the line in point-slope form that passes through the given point with the given slope. 5
ladessa [460]

Answer:

y-5=-3(x-1)           simplified: y=-3x+8

Step-by-step explanation:

y-y1=m(x-x1)

plug in point and slope given

y-5=-3(x-1)

y=-3x+3+5

y=-3x+8

3 0
3 years ago
What is tan(x)-5=0<br> (With steps)
gizmo_the_mogwai [7]
\tan x-5=0
\tan x=5

Now before taking the inverse tangent of both sides, recall that

\tan x=\tan(x\pm\pi)=\tan(x\pm2\pi)=\cdots=\tan(x\pm n\pi)

where n is any integer. This means that when taking the inverse tangent of \tan x, instead of just x, we would end up with

\arctan(\tan x)=\arctan(\tan(x+n\pi))=x\pm n\pi

So after doing so in the equation above, we're left with

x\pm n\pi=\arctan5\implies x=\arctan5\pm n\pi

As n can be any integer, including negative integers, we can simply write

x=\arctan5+n\pi,\,n\in\mathbb Z
8 0
4 years ago
A rectangular piece of paper has a width that is 3 inches less than its length. It is cut in half along a diagonal to create two
Oliga [24]

Let

x-------> the length of the rectangle

y------> the width of the rectangle

we know that

The area of the rectangle is equal to

A=x*y

The area of the two congruent right triangles  is equal to the area of the rectangle

A=2*44=88\ in^{2}

so

88=x*y -------> equation A

y=x-3 -----> equation B

Substitute equation B in equation A

x*[x-3]=88

x^{2} -3x-88=0 --------> equation that can be used  to solve for the length of the rectangle

Using a graph tool-------> solve the quadratic equation

see the attached figure

The solution is

x=11\ in -----> the length of the rectangle

Find the value of y

88=11*y

y=8\ in  ----> the width of the rectangle

Statements

<u>case A)</u> The area of the rectangle is 88 square inches

The statement is True

See the procedure

<u>Case B)</u> The equation  x*[x-3]=44 can be used to solve for the dimensions of the triangle

The statement is False

Because, the equation x*[x-3]=88 can be used to solve for the dimensions of the triangle

<u>case C)</u> The equation x^{2} -3x-88=0 can be used to solve for the length of the rectangle

The statement is True

see the procedure

<u>case D)</u>The triangle has a base of 11 inches and a height of 8 inches

The statement is True

Because, the base of the triangle is equal to the length of the rectangle and the height of the triangle is equal to the width of the rectangle

<u>case E)</u> The rectangle has a width of 4 inches

The statement is False

See the procedure

8 0
3 years ago
Read 2 more answers
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