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3 years ago

How do i wright an equation for slope and intercept

Mathematics

2 answers:

Alex17521 [72]3 years ago

3 0

Answer:

Step-by-step explanation:

the slope equation is (y2-y1)/(x2-x1)

Delvig [45]3 years ago

3 0

Answer:

The slope intercept form is: y = mx + b

m is the slope which is change in y over change in x.

b is the value of y when x is 0

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Simplify this expression (5)^ -5 (5)^ 7 please explain how you got the answer

Rina8888 [55]

Answer:

$( {5}^{ - 5} ) \times ( {5}^{7} ) \\ \\ \frac{ {5}^{7} }{ {5}^{5} } = {5}^{7 - 5} = {5}^{2}$

the answer is b. 25

3 0

3 years ago

Which number is between 1/6 and 0.25?

Airida [17]

$\displaystyle \frac{1}{6} = 0.16 \\ \\ 0.16 , \boxed{0.17 ,0.18,0.19,0.20,0.21,0.22,0.23,0.24},0.25$

5 0

2 years ago

Find the area of the shape shown below. NEED HELP ASAPPPPPPPPP

Fittoniya [83]

Answer: A = 7 unit^2

Explanation:

First let’s cut the shape into 1 square and 1 trapezoid.

After that we can calculate the 2 polygons individually

Find area of square:

A = 2 x 2 = 4

Find area of trapezoid:

A = (2 + 1)2/2 = 3

Find area of the whole shape

7 0

2 years ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

ANSWER:

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

SOLUTION:

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

2 years ago

A Toblerone candy bar is in the shape of a triangular prism. The area of the base is 3 in 2and the height of the prism is 5 in.

Mrac [35]

Answer:

15 in³

Step-by-step explanation:

Volume of the prism:

V = Bh, where B- area of base, h- height

Given:

B = 3 in²
h = 5 in

Volume is:

V = 3*5 = 15 in³

8 0

2 years ago