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luda_lava [24]
3 years ago
8

4.) The time X (minutes) for a lab assistant to prepare the equipment for a certain experiment is believed to have a uniform dis

tribution with A = 20 and B = 50. What is the probability that preparation is within 2 minutes of the mean time?
Mathematics
1 answer:
Jet001 [13]3 years ago
8 0

Answer:

P(35-2 < X 35+2) = P(33< X< 37)= P(X

And using the cumulative distribution function we got:

P(35-2 < X 35+2) = P(33< X< 37)= P(X

The probability that preparation is within 2 minutes of the mean time is 0.134

Step-by-step explanation:

For this case we define the following random variable X= (minutes) for a lab assistant to prepare the equipment for a certain experiment , and the distribution for X is given by:

X \sim Unif (a= 20, b =50)

The cumulative distribution function is given by:

F(x) = \frac{x-a}{b-a} , a \leq X \leq b

The expected value is given by:

E(X) = \frac{a+b}{2} = \frac{20+50}{2}=35

And we want to find the following probability:

P(35-2 < X 35+2) = P(33< X< 37)

And we can find this probability on this way:

P(35-2 < X 35+2) = P(33< X< 37)= P(X

And using the cumulative distribution function we got:

P(35-2 < X 35+2) = P(33< X< 37)= P(X

The probability that preparation is within 2 minutes of the mean time is 0.134

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iVinArrow [24]

Answer:

7.5 hours

Step-by-step explanation:

We can model an equation for this problem.

We can write:

F=mt

Where

F is the final temperature (15 degrees we need)

m is the rate of temperature change (2 degrees per hour)

and

t is the time, in hours, it will take (we need to find this)

It is given,

F = 15

m = 2

So, t would be:

F = mt

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t = 15/2 = 7.5

So it will take 7.5 hours

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3 years ago
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skelet666 [1.2K]

Step-by-step explanation:

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g(x)=x^2-6x

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if the denominator is zero the number is undefined which makes it not in the domain of the function

set x^2-6x equal to 0

the values for x is 0 or 6

so the only value that is not in the domain of f°g is 0 and 6

Hope that helps :)

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