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Lana71 [14]
2 years ago
11

XY is a diameter of a circle and Z is a point on the circle such that ZY=6. If the area of the triangle XYZ is 18 square root 3

find the length of arc XZ

Mathematics
1 answer:
nataly862011 [7]2 years ago
5 0
<h2>Answer:</h2>

4π

<h2>Step-by-step explanation:</h2>

As shown in the diagram, triangle XYZ is a right triangle. Therefore, its area (A) is given by:

A = \frac{1}{2} x b x h      -------------(i)

Where;

A = 18\sqrt{3}

b = XZ = base of the triangle

h = YZ = height of the triangle = 6

<em>Substitute these values into equation(i) and solve as follows:</em>

18\sqrt{3} =  \frac{1}{2} x b x 6

18\sqrt{3} =  3b

<em>Divide through by 3</em>

6\sqrt{3} =  b

Therefore, b = XZ = 6\sqrt{3}

<em>Now, assume that the circle is centered at O;</em>

Triangle XOZ is isosceles, therefore the following are true;

(i) |OZ| = |OX|

(ii) XZO = ZXO = 30°

(iii) XOZ + XZO + ZXO = 180°   [sum of angles in a triangle]

=>  XOZ + 30° + 30° = 180°

=>  XOZ + 60° = 180°

=>  XOZ = 180° - 60°

=>  XOZ = 120°

Therefore we can calculate the radius |OZ| of the circle using sine rule as follows;

\frac{sin|XOZ|}{XZ} = \frac{sin|ZXO|}{OZ}

\frac{sin120}{6\sqrt{3} } = \frac{sin 30}{OZ}

\frac{\sqrt{3} /2}{6\sqrt{3} } = \frac{1/2}{|OZ|}

\frac{1}{12}  = \frac{1}{2|OZ|}

\frac{1}{6} = \frac{1}{|OZ|}

|OZ| = 6

The radius of the circle is therefore 6.

<em>Now, let's calculate the length of the arc XZ</em>

The length(L) of an arc is given by;

L = θ / 360 x 2 π r          ------------------(ii)

Where;

θ = angle subtended by the arc at the center.

r = radius of the circle.

In our case,

θ = ZOX = 120°

r = |OZ| = 6

Substitute these values into equation (ii) as follows;

L = 120/360 x 2π x 6

L = 4π

Therefore the length of the arc XZ is 4π

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Answer:

d = 0.666t , where d is in miles and t is in minutes.

d = 39.94h, where d is in miles and h is in hours.

Step-by-step explanation:

A car travels 2\frac{1}{3} = 2.33 miles in 3\frac{1}{2} = 3.5 minutes at a constant speed.

Let the relation between the distance (d) traveled by car in miles after traveling t minutes is d = kt ......... (1)

Now, putting d = 2.33 miles and t = 3.5 minutes in the above equation we get,

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So, the equation (1) becomes d = 0.666t. (Answer)

Let us assume that the relation between the distance (D) traveled by car in miles after traveling h hours is d = Kh ............ (2)

Now, putting D = 2.33 miles and T = 3.5/60 = 0.058 hours in the above equation, we get

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Answer:

Thus the length = 230 and width = 90.

Step-by-step explanation:

Farmer Fernanda wants to put a fence around her rectangular field. The length of the field is 40 feet less  than 3 times the width.

She has 320 feet of fencing.

Let the length of the rectangular fence be x and the width of the fence be y.

Then the relation between them is

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Also x + y = 320

Solving these equations,

320 - y = 3y - 40

4y = 360

y = 90

x = 230

Thus the length = 230 and width = 90.

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3 years ago
Callie has a new kitten. They can weigh 3 pounds less than half the weight of Callie‘s cat. Together the cat and kitten weigh 18
gavmur [86]

Answer:

The weight of cat is <u>14 pounds</u> and the weight of kitten is <u>4 pounds</u>.

Step-by-step explanation:

Given:

Callie has a new kitten. It can weigh 3 pounds less than half the weight of Callie‘s cat. Together the cat and kitten weigh 18 pounds.

Now, to find the weight of each animal:

Let the cat's weight be x.

And the kitten weight = \frac{x}{2} -3

Total weight of cat and kitten = 18 pounds.

Now, to set an equation to get the weight of each animal:

(x)+(\frac{x}{2}-3)=18

x+\frac{x}{2} -3=18

\frac{2x+x-6}{2} =18

\frac{3x-6}{2} =18

<em>Multiplying both sides by 2 we get:</em>

<em />3x-6=36<em />

<em>Adding both sides by 6 we get:</em>

<em />3x=42<em />

<em>Dividing both sides by 3 we get:</em>

<em />x=14\ pounds.<em />

<em>The weight of cat = 14 pounds.</em>

Substituting the value of x to get the kitten's weight:

\frac{x}{2} -3\\\\=\frac{14}{2}-3\\\\=7-3\\\\=4.

<em>The kitten's weight = 4 pounds.</em>

Therefore, the weight of cat is 14 pounds and the weight of kitten is 4 pounds.

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