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Answer:
E = 1.20 × N/C
V = 1800 V
x = 0.058 m
Explanation:
given data
radius = 15 cm
net charge = 3 × C
electric potential decreased = 500 V
solution
we get here electric field at the sphere’s surface that is
electric field at the sphere’s surface E = ............1
put here value
electric field at the sphere’s surface E =
E = 1.20 × N/C
and
potential on surface of sphere is
V = ................2
V =
V = 1800 V
and
now we get distance that is x
and we know here
ΔV = V(x) - V ..............3
substitute here value
-500V =
-500 V =
solve it we get x
x = 0.058 m