Which of the following sample planning factors would influence the sample size for a substantive test of details for a specific
2 answers:
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Answer:
The correct interpretation of the given problem is outlined in the following portion of the explanation.
Explanation:
On 2019,
Company purchased = $540,000
Life useful = 5 years
(1)...
On year 2019,
On putting the values, we get
⇒
⇒
Journal - Dr $108,000 in depreciation A/c.
(2)...
Assets A/c Dr $ 92,880, To reassess surplus $92,880
Now,
On putting the values, we get
⇒
⇒ (Gained revaluation)
(3)...
On year 2020,
On putting values,
⇒
⇒
Journal - Depreciation A/c Dr. $131,220
.
(4)...
Surplus revaluation: Dr $39,312
On putting values,
⇒
⇒ (Loss revaluation)
Answer:
UCL= <u>0.044</u>
LCL=<u>-0.004</u>
Explanation:
Use following formula to calculate the UCL and LCL
UCL = p + z
Where
P = defect rate = 2% = 0.02
z = sigma control chart limit = 3
n = samploe size = 300
PLacing values in the formula
UCL = 0.02+3
UCL = 0.02 + 3 x 0.008082904
UCL = 0.02 + 0.024248711
UCL = 0.044248711
UCL = 0.044
Now calculate LCL using folllowing formula
LCL = p - z
Where
P = defect rate = 2% = 0.02
z = sigma control chart limit = 3
n = samploe size = 300
PLacing values in the formula
LCL = 0.02 - 3
LCL = 0.02 - 3 x 0.008082904
LCL = 0.02 - 0.024248711
LCL = -0.004248711
LCL = -0.004