Which filter gives a “squeezed” effect to an image?
1 answer:
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Answer:
Following are the code to this question:
public class ArrayMath//defining a class ArrayMath
{
public static void main(String[] args) //defining main method
{
int x[][]=new int[10][10]; //defining a 2D array
arrays(x);//calling a method arrays by passing an array
}
private static void arrays(int[][] x)//defining a method arrays
{
int odd_column_sum=0,sum_of_Elements=0,i,j,even=1;//defining integer variable
for(i=0;i<x.length;i++)//defining loop for columns
{
for(j=0;j<x[0].length;j++)//defining loop for rows
{
x[i][j]=i*j;//multiply the i and j value atore in array
}
}
System.out.println("::The 2D array :: ");//print message
for(i=0;i<x.length;i++)//defining loop for columns
{
System.out.print("\t");//use print method for line space and line break
for(j=0;j<x[0].length;j++)//defining loop for rows
{
System.out.printf("%d\t",x[i][j]); //print array values
}
System.out.println( );//print for line break
}
for(i=0;i<x.length;i++) //defining loop for Columns
{
for(j=0;j<x[0].length;j++) //defining loop for rows
{
if(even%2!=0)//defining if block for check odd number condition
{
odd_column_sum+=x[j][i];//add odd number of array
}
sum_of_Elements+=x[i][j];//add even number of array
}
even++;//increment even variable value by 1
}
System.out.println("The sum of Odd Columns:"+odd_column_sum);//print odd_column_sum value
System.out.println("The array elements :"+sum_of_Elements);//print sum_of_Elements value
}
}
Output:
please find attached file.
Explanation:
In the above-given code, a class "ArrayMath" is defined, inside the class the main method is declared, which define a 2D array "x", this stores 10 columns and 10 rows and at the last, we call the arrays method by passing an array as a variable.
In the arrays method, integer variable, "odd_column_sum, sum_of_Elements, i, j, and even" is defined, in which variable "i and j" is used in the loop for calculating value, even is used to check odd column and then store its value in the "odd_column_sum" variable, and add whole element value is added into the "sum_of_Elements" variable.
Answer:
Step by step code along with explanation and output is given below
Explanation:
We can solve this problem using if elif else approach
def main():
# prompts the user to enter an integer from 1 to 10
num = int (input('Enter a number in the range of 1 to 10:\n'))
# using the if elif print out the roman numeral from 1 to 10
if num == 1:
print ('Roman Numeral for 1 is I')
elif num == 2:
print ('Roman Numeral for 2 is II')
elif num == 3:
print ('Roman Numeral for 3 is III')
elif num == 4:
print ('Roman Numeral for 4 is IV')
elif num == 5:
print ('Roman Numeral for 5 is V')
elif num == 6:
print ('Roman Numeral for 6 is VI')
elif num == 7:
print ('Roman Numeral for 7 is VII')
elif num == 8:
print ('Roman Numeral for 8 is VIII')
elif num == 9:
print ('Roman Numeral for 9 is IX')
elif num == 10:
print ('Roman Numeral for 10 is X')
# using the else print out error message whenever user enters any other number not listed above
else:
print ('Error! Wrong Input')
# call the main function
main()
Output:
Enter a number in the range of 1 to 10:
6
Roman Numeral for 6 is VI
Enter a number in the range of 1 to 10:
15
Error! Wrong Input
