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3 years ago

R^3 +4r^2-25r-100 Help

Mathematics

1 answer:

Marina86 [1]3 years ago

7 0

Answer:

The zeroes in this equation are -5, -4, and 5

Step-by-step explanation:

In order to find these, you need to factor by splitting. For this, we separate out the two halves of the equation and pull out the greatest common factor of each. Let's start with the front end.

r^3 + 4r^2

r^2(r + 4)

Now the second half.

-25r - 100

-25(r + 4)

Since what is left in the parenthesis are exactly the same, we can use that parenthesis next to one with what we pulled out.

(r^2 - 25)(r + 4)

And we can further factor the first parenthesis using the difference of two squares

(r^2 - 25)(r + 4)

(r + 5)(r - 5)(r + 4)

Now that we are fully factored, set each parenthesis equal to 0 and solve for x.

r + 5 = 0

r = -5

r - 5 = 0

r = 5

r + 4 = 0

r = -4

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45/5+90+66/2

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Step-by-step explanation:

The null hypothesis is

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The alternative hypothesis is

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The p value that he got is 0.1499. This is greater than alpha = 0.05 which is the given level of significance.

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Therefore, the correct option is

No, these results are not statistically significant because p>0.05

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A study was conducted to compare the proportion of drivers in Boston and New York who wore seat belts while driving. Data were c

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(A.)test statistic for this test using Ha: p8くPN is Z = -2.164 (B.) p-value (3 decimal places) is 0.015. (C.) Based on this p-value, which of the following would you expect for a 95% is negative. (D.) the correct conclusion is The proportion of Boston drivers wearing seat was significantly lower than the proportion of new York drivers wearing seat belts.

A.)

According to given data find the test statistic for this test using Ha:

p1 = 0.581

p2 = 0.832

standard error = SE = 0.116

<h3>Test statistics :-</h3>

Z = $\frac{p1 - p2}{SE}$

Z = $\frac{0.581 - 0.832}{0.116}$ = -2.164

Z = -2.164

B.)

According to given Determine the p-value (3 decimal places).

<h3>p - value</h3>

it is left tailed test.

p - value for left tailed test is,

p - value = P(Z < test statistics )

p - value = P(Z < -2.164)

P - value = 0.015

C.)

Based on this p-value, which of the following would you expect for a 95%

confidence level = 95% = 0.95

significance level = α = 0.05

P -value is less than 0.05

so, reject null hypothesis at α = 0.05

That is $P_{B}$ < $P_{NY}$

so, based on P - value , All values in the 95% confidence interval

PB - PNY is negative.

D.)

According to given data What is the correct conclusion?

Reject null hypothesis at α = 0.05

so, $P_{B}$ < $P_{NY}$

Hence, The proportion of Boston drivers wearing seat was significantly lower than the proportion of new York drivers wearing seat belts.

know more about test statics visit this link

brainly.com/question/23332597

#SPJ4

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