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AlladinOne [14]
3 years ago
12

R^3 +4r^2-25r-100 Help

Mathematics
1 answer:
Marina86 [1]3 years ago
7 0

Answer:

The zeroes in this equation are -5, -4, and 5

Step-by-step explanation:

In order to find these, you need to factor by splitting. For this, we separate out the two halves of the equation and pull out the greatest common factor of each. Let's start with the front end.

r^3 + 4r^2

r^2(r + 4)

Now the second half.

-25r - 100

-25(r + 4)

Since what is left in the parenthesis are exactly the same, we can use that parenthesis next to one with what we pulled out.

(r^2 - 25)(r + 4)

And we can further factor the first parenthesis using the difference of two squares

(r^2 - 25)(r + 4)

(r + 5)(r - 5)(r + 4)

Now that we are fully factored, set each parenthesis equal to 0 and solve for x.

r + 5 = 0

r = -5

r - 5 = 0

r = 5

r + 4 = 0

r = -4

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Ok first lets take care of the color
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if 12=4 than blue=5
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there are 108 triangles in total
now since the ratio for triangle square or circle is 
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t3:s6:c1
since there are 108 triangles
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since for every 3 triangles there are 6 squares 
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4 0
3 years ago
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Answer:

1) 1: 107

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