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garik1379 [7]
3 years ago
9

Solve the equation (-7) (-5)

Mathematics
1 answer:
Tanzania [10]3 years ago
6 0
The answer is 35 i think but i am not sure
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ASAP help and thank you
Anestetic [448]

Answer:

The correct answer is A. and B.

Step-by-step explanation:

If it's flipped over to the other side, it will still be the same shape and the same size.

(:

5 0
3 years ago
Read 2 more answers
The cost of producing x pumpkin pies at a small bakery is given by c(x)=49+1.75x. Find the cost of producing 25 pies A. $74.00 B
luda_lava [24]
So basically you wanna look at the equation like this, you have the base price of 49$ no matter what. Now you need to find what 1.75 x 25 is which is 43.75. So now you add the 49 and 43.75  giving you C: $92.75. Hope this helps :D
7 0
3 years ago
Let h(x)=20e^kx where k ɛ R (Picture attached. Thank you so much!)
zloy xaker [14]

Answer:

A)

k=0

B)

\displaystyle \begin{aligned} 2k + 1& = 2\ln 20 + 1 \\ &\approx 2.3863\end{aligned}

C)

\displaystyle \begin{aligned} k - 3&= \ln \frac{1}{2} - 3 \\ &\approx-3.6931 \end{aligned}

Step-by-step explanation:

We are given the function:

\displaystyle h(x) = 20e^{kx} \text{ where } k \in \mathbb{R}

A)

Given that h(1) = 20, we want to find <em>k</em>.

h(1) = 20 means that <em>h</em>(x) = 20 when <em>x</em> = 1. Substitute:

\displaystyle (20) = 20e^{k(1)}

Simplify:

1= e^k

Anything raised to zero (except for zero) is one. Therefore:

k=0

B)

Given that h(1) = 40, we want to find 2<em>k</em> + 1.

Likewise, this means that <em>h</em>(x) = 40 when <em>x</em> = 1. Substitute:

\displaystyle (40) = 20e^{k(1)}

Simplify:

\displaystyle 2 = e^{k}

We can take the natural log of both sides:

\displaystyle \ln 2 = \underbrace{k\ln e}_{\ln a^b = b\ln a}

By definition, ln(e) = 1. Hence:

\displaystyle k = \ln 2

Therefore:

2k+1 = 2\ln 2+ 1 \approx 2.3863

C)

Given that h(1) = 10, we want to find <em>k</em> - 3.

Again, this meas that <em>h</em>(x) = 10 when <em>x</em> = 1. Substitute:

\displaystyle (10) = 20e^{k(1)}

Simplfy:

\displaystyle \frac{1}{2} = e^k

Take the natural log of both sides:

\displaystyle \ln \frac{1}{2} = k\ln e

Therefore:

\displaystyle k = \ln \frac{1}{2}

Therefore:

\displaystyle k - 3 = \ln\frac{1}{2} - 3\approx-3.6931

3 0
2 years ago
What is the slope and y intercept of -2x +3y=-9
attashe74 [19]

Answer:

m = 2/3

b = -3

Step-by-step explanation:

Rearrange the equation to slope-intercept form (y = mx + b).

x and y are points on the graph.

m is the slope.

b is the y-intercept.

Isolate "y". This means separating it from the other numbers.

-2x +3y = -9

-2x + 2x +3y = -9 + 2x    Add 2x to both sides

3y = 2x - 9

3y/3 = 2x/3 - 9/3      Divide both sides by 3

y = 2x/3 - 9/3      Simplify

y = (2/3)x - 3

Think about which numbers and "m" and "b" now that the equation is in y = mx + b. Include the plus and minus signs.

m = 2/3

b = -3

8 0
2 years ago
Solve the equation. \dfrac{11}6 =n+\dfrac79 6 11 ​ =n+ 9 7 ​ start fraction, 11, divided by, 6, end fraction, equals, n, plus, s
kvasek [131]
11/6 = n + 7/9
11/6 - 7/9 = n = 19/18
5 0
3 years ago
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