Answer:
Step-by-step explanation:
a)
Number of sample, n = 100
p = 0.78
q = 1 - p = 1 - 0.78
q = 0.22
For a confidence level of 90%, the corresponding z value is 1.645.
The formula for determining the error bound for the proportion is
z × √pq/n
= 1.645 ×√(0.78 × 0.22)/100
= 1.645 × 0.0414 = 0.068
The upper boundary of the population proportion is
0.78 + 0.068 = 0.85
The lower boundary of the population proportion is
0.78 - 0.068 = 0.71
b) For a confidence level of 95%, the corresponding z value is 1.96.
Therefore,
= 1.96 ×√(0.78 × 0.22)/100
= 1.96 × 0.0414 = 0.081
The upper boundary of the population proportion is
0.78 + 0.081 = 0.86
The lower boundary of the population proportion is
0.78 - 0.081 = 0.7
Answer:
Denote:
A(-10, -10)
B(6, -2)
vector AB(6 - -10, -2 - -10) = (16, 8)
(3/5)vector AB = (16 x 3/5, 8 x 3/5) = (9.6, 4.8)
=> Point M that partitions the directed line segment AB into a ratio of 3 to 5:
M = A + (3/5)vector AB = (-10 + 9,6, -10 + 4.8) = (-0.4, -5.2)
Hope this helps!
:)
Distance to checkpoint A from starting line = 20 yards.
Then from A to B distance = 12 yards.
Let us take starting point C.
So, it would make a right triangle.
We have AB = 12, AC = 20, we need to find BC, that is Hypotenuse of the right triangle.
According to Pythagoras theorem:
BC = 23.32.
<h3>Therefore, 23.32 yards is the distance from Checkpoint B to the starting line.</h3>
Answer:
The Answer is 12 days or times.
Step-by-step explanation:
The LCM of 6 is 3 and 2, the LCM of 4 is 2 and 1, so we multiply 3 by 2 and 4 by 2 together to get 12, which is the number of days or times.
Answer:
Follows are the solution to this question:
Step-by-step explanation:
Please find the attached file for the complete solution.
